detailed information: The input equation set is:
| | | | | 7 10 | A | + | | | 3 10 | B | + | | | 3 10 | E | = | | 34 | | (1) |
| | | 2 5 | A | + | | | 1 2 | D | + | | | 1 2 | E | = | | | 63 2 | | (2) |
| | | | 1 2 | B | + | | | 1 2 | C | + | | | 1 2 | E | = | | | 73 2 | | (4) |
| | Question solving process:
Multiply both sides of equation (1) by 4 Divide the two sides of equation (1) by 7, the equation can be obtained: | | | 2 5 | A | + | | | 6 35 | B | + | | | 6 35 | E | = | | | 136 7 | (6) | , then subtract both sides of equation (6) from both sides of equation (2), the equations are reduced to:
| | | | | 7 10 | A | + | | | 3 10 | B | + | | | 3 10 | E | = | | 34 | | (1) |
| - | 6 35 | B | + | | | 1 2 | D | + | | | 23 70 | E | = | | | 169 14 | | (2) |
| | | | 1 2 | B | + | | | 1 2 | C | + | | | 1 2 | E | = | | | 73 2 | | (4) |
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Multiply both sides of equation (2) by 35 Divide the two sides of equation (2) by 12, the equation can be obtained: | - | 1 2 | B | + | | | 35 24 | D | + | | | 23 24 | E | = | | | 845 24 | (7) | , then add the two sides of equation (7) to both sides of equation (4), the equations are reduced to:
| | | | | 7 10 | A | + | | | 3 10 | B | + | | | 3 10 | E | = | | 34 | | (1) |
| - | 6 35 | B | + | | | 1 2 | D | + | | | 23 70 | E | = | | | 169 14 | | (2) |
| | | | 1 2 | C | + | | | 35 24 | D | + | | | 35 24 | E | = | | | 1721 24 | | (4) |
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Subtract both sides of equation (3) from both sides of equation (4) ,the equations are reduced to:
| | | | | 7 10 | A | + | | | 3 10 | B | + | | | 3 10 | E | = | | 34 | | (1) |
| - | 6 35 | B | + | | | 1 2 | D | + | | | 23 70 | E | = | | | 169 14 | | (2) |
| | | | 23 24 | D | + | | | 23 24 | E | = | | | 905 24 | | (4) |
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Subtract both sides of equation (3) from both sides of equation (5) ,the equations are reduced to:
| | | | | 7 10 | A | + | | | 3 10 | B | + | | | 3 10 | E | = | | 34 | | (1) |
| - | 6 35 | B | + | | | 1 2 | D | + | | | 23 70 | E | = | | | 169 14 | | (2) |
| | | | 23 24 | D | + | | | 23 24 | E | = | | | 905 24 | | (4) |
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Multiply both sides of equation (4) by 12 Divide the two sides of equation (4) by 23, the equation can be obtained: , then add the two sides of equation (8) to both sides of equation (5), the equations are reduced to:
| | | | | 7 10 | A | + | | | 3 10 | B | + | | | 3 10 | E | = | | 34 | | (1) |
| - | 6 35 | B | + | | | 1 2 | D | + | | | 23 70 | E | = | | | 169 14 | | (2) |
| | | | 23 24 | D | + | | | 23 24 | E | = | | | 905 24 | | (4) |
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Multiply both sides of equation (5) by 23 Divide both sides of equation (5) by 12, get the equation:, then subtract both sides of equation (9) from both sides of equation (4), get the equation:
| | | | | 7 10 | A | + | | | 3 10 | B | + | | | 3 10 | E | = | | 34 | | (1) |
| - | 6 35 | B | + | | | 1 2 | D | + | | | 23 70 | E | = | | | 169 14 | | (2) |
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Subtract both sides of equation (5) from both sides of equation (3), get the equation:
| | | | | 7 10 | A | + | | | 3 10 | B | + | | | 3 10 | E | = | | 34 | | (1) |
| - | 6 35 | B | + | | | 1 2 | D | + | | | 23 70 | E | = | | | 169 14 | | (2) |
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Multiply both sides of equation (5) by 23 Divide both sides of equation (5) by 35, get the equation:, then subtract both sides of equation (10) from both sides of equation (2), get the equation:
| | | | | 7 10 | A | + | | | 3 10 | B | + | | | 3 10 | E | = | | 34 | | (1) |
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Multiply both sides of equation (5) by 3 Divide both sides of equation (5) by 5, get the equation:, then subtract both sides of equation (11) from both sides of equation (1), get the equation:
Multiply both sides of equation (4) by 12 Divide both sides of equation (4) by 23, get the equation:, then subtract both sides of equation (12) from both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 12 Divide both sides of equation (4) by 23, get the equation:, then subtract both sides of equation (13) from both sides of equation (2), get the equation:
Multiply both sides of equation (2) by 7 Divide both sides of equation (2) by 4, get the equation:, then add the two sides of equation (14) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |