detailed information: The input equation set is: Question solving process:
Divide the two sides of equation (1) by 3, the equation can be obtained: , then subtract both sides of equation (6) from both sides of equation (2), the equations are reduced to:
Divide the two sides of equation (1) by 3, the equation can be obtained: , then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
Divide the two sides of equation (1) by 3, the equation can be obtained: , then add the two sides of equation (8) to both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (2) by 7 Divide the two sides of equation (2) by 5, the equation can be obtained: | - | 7 3 | B | + | | | 7 5 | C | | - | 14 15 | E | = | | 0 | (9) | , then subtract both sides of equation (9) from both sides of equation (3), the equations are reduced to:
Multiply both sides of equation (2) by 3 Divide the two sides of equation (2) by 5, the equation can be obtained: , then subtract both sides of equation (10) from both sides of equation (4), the equations are reduced to:
Multiply both sides of equation (2) by 2 Divide the two sides of equation (2) by 5, the equation can be obtained: | - | 2 3 | B | + | | | 2 5 | C | | - | 4 15 | E | = | | 0 | (11) | , then add the two sides of equation (11) to both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (3) by 3 Divide the two sides of equation (3) by 2, the equation can be obtained: , then subtract both sides of equation (12) from both sides of equation (4), the equations are reduced to:
Multiply both sides of equation (3) by 7 Divide the two sides of equation (3) by 12, the equation can be obtained: , then add the two sides of equation (13) to both sides of equation (5), the equations are reduced to:
交After the exchange of equation (4) and equation (5), the equation system becomes:
Multiply both sides of equation (4) by 12 Divide both sides of equation (4) by 25, get the equation:, then subtract both sides of equation (14) from both sides of equation (3), get the equation:
Multiply both sides of equation (4) by 4 Divide both sides of equation (4) by 5, get the equation:, then subtract both sides of equation (15) from both sides of equation (2), get the equation:
Multiply both sides of equation (4) by 6 Divide both sides of equation (4) by 5, get the equation:, then subtract both sides of equation (16) from both sides of equation (1), get the equation:
Multiply both sides of equation (3) by 5 Divide both sides of equation (3) by 12, get the equation:, then add the two sides of equation (17) to both sides of equation (2), get the equation:
Multiply both sides of equation (2) by 3 Divide both sides of equation (2) by 5, get the equation:, then subtract both sides of equation (18) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
Where: D are arbitrary constants. 解方程组的详细方法请参阅:《多元一次方程组的解法》 |