Mathematics
         
语言:中文    Language:English
On line solution of multivariate equations:
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location:Equations > Multivariate equations > Answer
detailed information:
The input equation set is:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
 A + 6E -3F = 0    (3)
 B -1D -1E = 0    (4)
 C + D -1F = 0    (5)
 A -1B -1C = 0    (6)
Question solving process:

Divide the two sides of equation (1) by 5, the equation can be obtained:
         A + 
2
5
C + 
3
5
F = 
16
5
    (7)
, then subtract both sides of equation (7) from both sides of equation (3), the equations are reduced to:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
 B -1D -1E = 0    (4)
 C + D -1F = 0    (5)
 A -1B -1C = 0    (6)

Divide the two sides of equation (1) by 5, the equation can be obtained:
         A + 
2
5
C + 
3
5
F = 
16
5
    (8)
, then subtract both sides of equation (8) from both sides of equation (6), the equations are reduced to:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
 B -1D -1E = 0    (4)
 C + D -1F = 0    (5)
-1B 
7
5
C 
3
5
F = 
16
5
    (6)

Subtract both sides of equation (2) from both sides of equation (4) ,the equations are reduced to:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
 C -1D -1E = 0    (4)
 C + D -1F = 0    (5)
-1B 
7
5
C 
3
5
F = 
16
5
    (6)

Add both sides of equation (2) to both sides of equation (6) ,the equations are reduced to:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
 C -1D -1E = 0    (4)
 C + D -1F = 0    (5)
12
5
C 
3
5
F = 
16
5
    (6)

Multiply both sides of equation (3) by 5
Divide the two sides of equation (3) by 2, the equation can be obtained:
        -1C + 15E -9F = -8    (9)
, then add the two sides of equation (9) to both sides of equation (4), the equations are reduced to:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
-1D + 14E -9F = -8    (4)
 C + D -1F = 0    (5)
12
5
C 
3
5
F = 
16
5
    (6)

Multiply both sides of equation (3) by 5
Divide the two sides of equation (3) by 2, the equation can be obtained:
        -1C + 15E -9F = -8    (10)
, then add the two sides of equation (10) to both sides of equation (5), the equations are reduced to:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
-1D + 14E -9F = -8    (4)
 D + 15E -10F = -8    (5)
12
5
C 
3
5
F = 
16
5
    (6)

Multiply both sides of equation (3) by 6, the equation can be obtained:
        
12
5
C + 36E 
108
5
F = 
96
5
    (11)
, then subtract both sides of equation (11) from both sides of equation (6), the equations are reduced to:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
-1D + 14E -9F = -8    (4)
 D + 15E -10F = -8    (5)
-36E + 21F = 16    (6)

Add both sides of equation (4) to both sides of equation (5) ,the equations are reduced to:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
-1D + 14E -9F = -8    (4)
 29E -19F = -16    (5)
-36E + 21F = 16    (6)

Multiply both sides of equation (5) by 36
Divide the two sides of equation (5) by 29, the equation can be obtained:
         36E 
684
29
F = 
576
29
    (12)
, then add the two sides of equation (12) to both sides of equation (6), the equations are reduced to:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
-1D + 14E -9F = -8    (4)
 29E -19F = -16    (5)
75
29
F = 
112
29
    (6)

Multiply both sides of equation (6) by 551
Divide both sides of equation (6) by 75, get the equation:
        -19F = 
2128
75
    (13)
, then subtract both sides of equation (13) from both sides of equation (5), get the equation:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
-1D + 14E -9F = -8    (4)
 29E = 
928
75
    (5)
75
29
F = 
112
29
    (6)

Multiply both sides of equation (6) by 87
Divide both sides of equation (6) by 25, get the equation:
        -9F = 
336
25
    (14)
, then subtract both sides of equation (14) from both sides of equation (4), get the equation:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E 
18
5
F = 
16
5
    (3)
-1D + 14E = 
136
25
    (4)
 29E = 
928
75
    (5)
75
29
F = 
112
29
    (6)

Multiply both sides of equation (6) by 174
Divide both sides of equation (6) by 125, get the equation:
        
18
5
F = 
672
125
    (15)
, then subtract both sides of equation (15) from both sides of equation (3), get the equation:
 5A + 2C + 3F = 16    (1)
 B -1C = 0    (2)
2
5
C + 6E = 
272
125
    (3)
-1D + 14E = 
136
25
    (4)
 29E = 
928
75
    (5)
75
29
F = 
112
29
    (6)

Multiply both sides of equation (6) by 29
Divide both sides of equation (6) by 25, get the equation:
        -3F = 
112
25
    (16)
, then add the two sides of equation (16) to both sides of equation (1), get the equation:
 5A + 2C = 
288
25
    (1)
 B -1C = 0    (2)
2
5
C + 6E = 
272
125
    (3)
-1D + 14E = 
136
25
    (4)
 29E = 
928
75
    (5)
75
29
F = 
112
29
    (6)

Multiply both sides of equation (5) by 14
Divide both sides of equation (5) by 29, get the equation:
         14E = 
448
75
    (17)
, then subtract both sides of equation (17) from both sides of equation (4), get the equation:
 5A + 2C = 
288
25
    (1)
 B -1C = 0    (2)
2
5
C + 6E = 
272
125
    (3)
-1D = 
8
15
    (4)
 29E = 
928
75
    (5)
 F = 
112
75
    (6)

Multiply both sides of equation (5) by 6
Divide both sides of equation (5) by 29, get the equation:
         6E = 
64
25
    (18)
, then subtract both sides of equation (18) from both sides of equation (3), get the equation:
 5A + 2C = 
288
25
    (1)
 B -1C = 0    (2)
2
5
C = 
48
125
    (3)
-1D = 
8
15
    (4)
 29E = 
928
75
    (5)
 F = 
112
75
    (6)

Multiply both sides of equation (3) by 5
Divide both sides of equation (3) by 2, get the equation:
        -1C = 
24
25
    (19)
, then subtract both sides of equation (19) from both sides of equation (2), get the equation:
 5A + 2C = 
288
25
    (1)
 B = 
24
25
    (2)
2
5
C = 
48
125
    (3)
 D = 
8
15
    (4)
 E = 
32
75
    (5)
 F = 
112
75
    (6)

Multiply both sides of equation (3) by 5, get the equation:
        -2C = 
48
25
    (20)
, then add the two sides of equation (20) to both sides of equation (1), get the equation:
 5A = 
48
5
    (1)
 B = 
24
25
    (2)
2
5
C = 
48
125
    (3)
 D = 
8
15
    (4)
 E = 
32
75
    (5)
 F = 
112
75
    (6)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
 A = 
48
25
    (1)
 B = 
24
25
    (2)
 C = 
24
25
    (3)
 D = 
8
15
    (4)
 E = 
32
75
    (5)
 F = 
112
75
    (6)


Therefore, the solution of the equation set is:
A = 
48
25
B = 
24
25
C = 
24
25
D = 
8
15
E = 
32
75
F = 
112
75


Convert the solution of the equation set to decimals:
A = 1.920000
B = 0.960000
C = 0.960000
D = 0.533333
E = 0.426667
F = 1.493333

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