detailed information: The input equation set is:
| | | | | 111 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (1) |
| | | 199 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (2) |
| | | 199 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (3) |
| | | 199 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (4) |
| | | 199 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (5) |
| Question solving process:
Multiply both sides of equation (1) by 199 Divide the two sides of equation (1) by 111, the equation can be obtained: | | | 199 100 | A | + | | | 39601 11100 | B | + | | | 59501 11100 | C | + | | | 26467 3700 | D | + | | | 1990 111 | E | = | | 0 | (6) | , then subtract both sides of equation (6) from both sides of equation (2), the equations are reduced to:
| | | | | 111 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (1) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (2) |
| | | 199 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (3) |
| | | 199 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (4) |
| | | 199 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (5) |
|
Multiply both sides of equation (1) by 199 Divide the two sides of equation (1) by 111, the equation can be obtained: | | | 199 100 | A | + | | | 39601 11100 | B | + | | | 59501 11100 | C | + | | | 26467 3700 | D | + | | | 1990 111 | E | = | | 0 | (7) | , then subtract both sides of equation (7) from both sides of equation (3), the equations are reduced to:
| | | | | 111 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (1) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (2) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (3) |
| | | 199 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (4) |
| | | 199 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (5) |
|
Multiply both sides of equation (1) by 199 Divide the two sides of equation (1) by 111, the equation can be obtained: | | | 199 100 | A | + | | | 39601 11100 | B | + | | | 59501 11100 | C | + | | | 26467 3700 | D | + | | | 1990 111 | E | = | | 0 | (8) | , then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
| | | | | 111 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (1) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (2) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (3) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (4) |
| | | 199 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (5) |
|
Multiply both sides of equation (1) by 199 Divide the two sides of equation (1) by 111, the equation can be obtained: | | | 199 100 | A | + | | | 39601 11100 | B | + | | | 59501 11100 | C | + | | | 26467 3700 | D | + | | | 1990 111 | E | = | | 0 | (9) | , then subtract both sides of equation (9) from both sides of equation (5), the equations are reduced to:
| | | | | 111 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (1) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (2) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (3) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (4) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (5) |
|
Subtract both sides of equation (2) from both sides of equation (3) ,the equations are reduced to:
| | | | | 111 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (1) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (2) |
| | - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (4) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (5) |
|
Subtract both sides of equation (2) from both sides of equation (4) ,the equations are reduced to:
| | | | | 111 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (1) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (2) |
| | | - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (5) |
|
Subtract both sides of equation (2) from both sides of equation (5) ,the equations are reduced to:
| | | | | 111 100 | A | + | | | 199 100 | B | + | | | 299 100 | C | + | | | 399 100 | D | + | | 10 | E | = | | 0 | | (1) |
| - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (2) |
| | | |
Multiply both sides of equation (2) by 22089 Divide both sides of equation (2) by 17512, get the equation: | - | 39601 19900 | B | | - | 59501 19900 | C | | - | 79401 19900 | D | | - | 1990 199 | E | = | | 0 | (10) | , then add the two sides of equation (10) to both sides of equation (1), get the equation:
| | | | - | 4378 2775 | B | | - | 6578 2775 | C | | - | 2926 925 | D | | - | 880 111 | E | = | | 0 | | (2) |
| | | |
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
| | | | | B | + | | | 299 199 | C | + | | | 399 199 | D | + | | | 1000 199 | E | = | | 0 | | (2) |
| | | |
Therefore, the solution of the equation set is:
| | | | B = | - | | 299 199 | C | - | | | 399 199 | D | - | | | 1000 199 | E |
|
Where: C, D, E are arbitrary constants. 解方程组的详细方法请参阅:《多元一次方程组的解法》 |