detailed information: The input equation set is:
| | | | | -1 | A | | -1 | B | + | | 5 | C | + | | 2 | D | = | | -4 | | (3) |
| | Question solving process:
Divide the two sides of equation (1) by 4, the equation can be obtained: , then subtract both sides of equation (5) from both sides of equation (2), the equations are reduced to:
| | | | | -1 | A | | -1 | B | + | | 5 | C | + | | 2 | D | = | | -4 | | (3) |
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Divide the two sides of equation (1) by 4, the equation can be obtained: , then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
| | | | | - | 3 4 | B | + | | | 19 4 | C | + | | 2 | D | = | | - | 9 4 | | (3) |
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Multiply both sides of equation (2) by 3 Divide the two sides of equation (2) by 11, the equation can be obtained: , then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
Multiply both sides of equation (3) by 11 Divide the two sides of equation (3) by 25, the equation can be obtained: , then subtract both sides of equation (8) from both sides of equation (4), the equations are reduced to:
Multiply both sides of equation (4) by 25 Divide both sides of equation (4) by 39, get the equation:, then subtract both sides of equation (9) from both sides of equation (3), get the equation:
Multiply both sides of equation (3) by 33 Divide both sides of equation (3) by 200, get the equation:, then add the two sides of equation (10) to both sides of equation (2), get the equation:
Multiply both sides of equation (3) by 11 Divide both sides of equation (3) by 50, get the equation:, then add the two sides of equation (11) to both sides of equation (1), get the equation:
Multiply both sides of equation (2) by 4 Divide both sides of equation (2) by 11, get the equation:, then subtract both sides of equation (12) from both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |