detailed information: The input equation set is:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
| | -12 | A | | -6 | B | + | | 12 | C | | -6 | D | = | | 0 | | (3) |
| | | Question solving process:
Divide the two sides of equation (1) by 2, the equation can be obtained: | | 12 | A | | -6 | C | + | | 3 | D | | - | 5 2 | E | = | | 0 | (6) | , then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
| | -6 | B | + | | 6 | C | | -3 | D | | - | 5 2 | E | = | | 0 | | (3) |
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Divide the two sides of equation (1) by 4, the equation can be obtained: | | 6 | A | | -3 | C | + | | | 3 2 | D | | - | 5 4 | E | = | | 0 | (7) | , then subtract both sides of equation (7) from both sides of equation (4), the equations are reduced to:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
| | -6 | B | + | | 6 | C | | -3 | D | | - | 5 2 | E | = | | 0 | | (3) |
| | 2 | B | | -3 | C | + | | | 5 2 | D | + | | | 5 4 | E | = | | 0 | | (4) |
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Multiply both sides of equation (1) by 25 Divide the two sides of equation (1) by 6, the equation can be obtained: | | 100 | A | | -50 | C | + | | 25 | D | | - | 125 6 | E | = | | 0 | (8) | , then subtract both sides of equation (8) from both sides of equation (5), the equations are reduced to:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
| | -6 | B | + | | 6 | C | | -3 | D | | - | 5 2 | E | = | | 0 | | (3) |
| | 2 | B | | -3 | C | + | | | 5 2 | D | + | | | 5 4 | E | = | | 0 | | (4) |
| | 50 | C | | -25 | D | + | | | 155 6 | E | = | | -1 | | (5) |
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Multiply both sides of equation (2) by 3 Divide the two sides of equation (2) by 4, the equation can be obtained: , then add the two sides of equation (9) to both sides of equation (3), the equations are reduced to:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
| | | | 2 | B | | -3 | C | + | | | 5 2 | D | + | | | 5 4 | E | = | | 0 | | (4) |
| | 50 | C | | -25 | D | + | | | 155 6 | E | = | | -1 | | (5) |
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Divide the two sides of equation (2) by 4, the equation can be obtained: , then subtract both sides of equation (10) from both sides of equation (4), the equations are reduced to:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
| | | | | 50 | C | | -25 | D | + | | | 155 6 | E | = | | -1 | | (5) |
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Add both sides of equation (3) to both sides of equation (4) ,the equations are reduced to:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
| | | | | 50 | C | | -25 | D | + | | | 155 6 | E | = | | -1 | | (5) |
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Multiply both sides of equation (3) by 100 Divide the two sides of equation (3) by 3, the equation can be obtained: | | 50 | C | | -50 | D | | - | 250 3 | E | = | | 0 | (11) | , then subtract both sides of equation (11) from both sides of equation (5), the equations are reduced to:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
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Multiply both sides of equation (4) by 50, the equation can be obtained: , then subtract both sides of equation (12) from both sides of equation (5), the equations are reduced to:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
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Multiply both sides of equation (5) by 3 Divide both sides of equation (5) by 412, get the equation:, then add the two sides of equation (13) to both sides of equation (4), get the equation:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
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Multiply both sides of equation (5) by 3 Divide both sides of equation (5) by 206, get the equation:, then add the two sides of equation (14) to both sides of equation (3), get the equation:
| | | | 24 | A | | -12 | C | + | | 6 | D | | -5 | E | = | | 0 | | (1) |
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Multiply both sides of equation (5) by 3 Divide both sides of equation (5) by 103, get the equation:, then add the two sides of equation (15) to both sides of equation (1), get the equation:
| | | | 24 | A | | -12 | C | + | | 6 | D | = | | - | 3 103 | | (1) |
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Multiply both sides of equation (4) by 3, get the equation:, then add the two sides of equation (16) to both sides of equation (3), get the equation:
| | | | 24 | A | | -12 | C | + | | 6 | D | = | | - | 3 103 | | (1) |
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Multiply both sides of equation (4) by 4, get the equation:, then subtract both sides of equation (17) from both sides of equation (2), get the equation:
| | | | 24 | A | | -12 | C | + | | 6 | D | = | | - | 3 103 | | (1) |
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Multiply both sides of equation (4) by 12, get the equation:, then subtract both sides of equation (18) from both sides of equation (1), get the equation:
Multiply both sides of equation (3) by 4, get the equation:, then add the two sides of equation (19) to both sides of equation (2), get the equation:
Multiply both sides of equation (3) by 8, get the equation:, then add the two sides of equation (20) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |