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On line solution of multivariate equations：
    First set the elements of the equation (i.e. the number of unknowns), then click the "Next" button to enter the coefficients of each element of the equation set, and click the "Next" button to obtain the solution of the equation set.
    Note that the coefficients of each element of the equation system can only be numbers, not algebraic expressions (including mathematical functions).
    Current location：Equations > Multivariate equations > Answer
detailed information：
The input equation set is:
- 
1
10
A + 
1
10
B + C = 0    (1)
-2A -3B + 10D = 0    (2)
 20A + 4C = 113    (3)
 B + 100D = 0    (4)
Question solving process:

Multiply both sides of equation (1) by 20, the equation can be obtained:
        -2A + 2B + 20C = 0    (5)
, then subtract both sides of equation (5) from both sides of equation (2), the equations are reduced to:
- 
1
10
A + 
1
10
B + C = 0    (1)
-5B -20C + 10D = 0    (2)
 20A + 4C = 113    (3)
 B + 100D = 0    (4)

Multiply both sides of equation (1) by 200, the equation can be obtained:
        -20A + 20B + 200C = 0    (6)
, then add the two sides of equation (6) to both sides of equation (3), the equations are reduced to:
- 
1
10
A + 
1
10
B + C = 0    (1)
-5B -20C + 10D = 0    (2)
 20B + 204C = 113    (3)
 B + 100D = 0    (4)

Multiply both sides of equation (2) by 4, the equation can be obtained:
        -20B -80C + 40D = 0    (7)
, then add the two sides of equation (7) to both sides of equation (3), the equations are reduced to:
- 
1
10
A + 
1
10
B + C = 0    (1)
-5B -20C + 10D = 0    (2)
 124C + 40D = 113    (3)
 B + 100D = 0    (4)

Divide the two sides of equation (2) by 5, the equation can be obtained:
        -1B -4C + 2D = 0    (8)
, then add the two sides of equation (8) to both sides of equation (4), the equations are reduced to:
- 
1
10
A + 
1
10
B + C = 0    (1)
-5B -20C + 10D = 0    (2)
 124C + 40D = 113    (3)
-4C + 102D = 0    (4)

Divide the two sides of equation (3) by 31, the equation can be obtained:
         4C + 
40
31
D = 
113
31
    (9)
, then add the two sides of equation (9) to both sides of equation (4), the equations are reduced to:
- 
1
10
A + 
1
10
B + C = 0    (1)
-5B -20C + 10D = 0    (2)
 124C + 40D = 113    (3)
 
3202
31
D = 
113
31
    (4)

Multiply both sides of equation (4) by 620
Divide both sides of equation (4) by 1601, get the equation：
         
64040
1601
D = 
2260
1601
    (10)
, then subtract both sides of equation (10) from both sides of equation (3), get the equation：
- 
1
10
A + 
1
10
B + C = 0    (1)
-5B -20C + 10D = 0    (2)
 124C = 
178653
1601
    (3)
 
3202
31
D = 
113
31
    (4)

Multiply both sides of equation (4) by 155
Divide both sides of equation (4) by 1601, get the equation：
         
16010
1601
D = 
565
1601
    (11)
, then subtract both sides of equation (11) from both sides of equation (2), get the equation：
- 
1
10
A + 
1
10
B + C = 0    (1)
-5B -20C = - 
565
1601
    (2)
 124C = 
178653
1601
    (3)
 
3202
31
D = 
113
31
    (4)

Multiply both sides of equation (3) by 5
Divide both sides of equation (3) by 31, get the equation：
         20C = 
28815
1601
    (12)
, then add the two sides of equation (12) to both sides of equation (2), get the equation：
- 
1
10
A + 
1
10
B + C = 0    (1)
-5B = 
28250
1601
    (2)
 124C = 
178653
1601
    (3)
 D = 
113
3202
    (4)

Divide both sides of equation (3) by 124, get the equation：
         C = 
5763
6404
    (13)
, then subtract both sides of equation (13) from both sides of equation (1), get the equation：
- 
1
10
A + 
1
10
B = - 
5763
6404
    (1)
-5B = 
28250
1601
    (2)
 124C = 
178653
1601
    (3)
 D = 
113
3202
    (4)

Divide both sides of equation (2) by 50, get the equation：
        - 
1
10
B = 
565
1601
    (14)
, then add the two sides of equation (14) to both sides of equation (1), get the equation：
- 
1
10
A = - 
3503
6404
    (1)
-5B = 
28250
1601
    (2)
 C = 
5763
6404
    (3)
 D = 
113
3202
    (4)

The coefficient of the unknown number is reduced to 1, and the equations are reduced to：
 A = 
17515
3202
    (1)
 B = - 
5650
1601
    (2)
 C = 
5763
6404
    (3)
 D = 
113
3202
    (4)


Therefore, the solution of the equation set is:
A = 
17515
3202
B = - 
5650
1601
C = 
5763
6404
D = 
113
3202


Convert the solution of the equation set to decimals:
A = 5.470019
B = -3.529044
C = 0.899906
D = 0.035290

解方程组的详细方法请参阅：《多元一次方程组的解法》
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