detailed information: The input equation set is:
 | | | | 5 | x | + | | 10 | y | + | | 14 | z | = | | 2309 | | (1) |
| | | 8 | x | + | | 15 | y | + | | 23 | z | = | | 3500 | | (3) |
| Question solving process:
Subtract both sides of equation (1) from both sides of equation (2) ,the equations are reduced to:
 | | | | 5 | x | + | | 10 | y | + | | 14 | z | = | | 2309 | | (1) |
| | | 8 | x | + | | 15 | y | + | | 23 | z | = | | 3500 | | (3) |
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Multiply both sides of equation (1) by 8 Divide the two sides of equation (1) by 5, the equation can be obtained: | | 8 | x | + | | 16 | y | + | | | 112 5 | z | = | | | 18472 5 | (4) | , then subtract both sides of equation (4) from both sides of equation (3), the equations are reduced to:
 | | | | 5 | x | + | | 10 | y | + | | 14 | z | = | | 2309 | | (1) |
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Divide the two sides of equation (2) by 10, the equation can be obtained: , then subtract both sides of equation (5) from both sides of equation (3), the equations are reduced to:
 | | | | 5 | x | + | | 10 | y | + | | 14 | z | = | | 2309 | | (1) |
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Multiply both sides of equation (3) by 2, get the equation:, then subtract both sides of equation (6) from both sides of equation (2), get the equation:
 | | | | 5 | x | + | | 10 | y | + | | 14 | z | = | | 2309 | | (1) |
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Multiply both sides of equation (3) by 28, get the equation:, then subtract both sides of equation (7) from both sides of equation (1), get the equation:
Add both sides of equation (2) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |