detailed information: The input equation set is:
 | | | | | | | -10 | A | + | | 10 | B | + | | 4 | C | = | | -20 | | (5) |
| | Question solving process:
Multiply both sides of equation (1) by 2, the equation can be obtained: , then add the two sides of equation (7) to both sides of equation (4), the equations are reduced to:
 | | | | | | | -10 | A | + | | 10 | B | + | | 4 | C | = | | -20 | | (5) |
| |
Multiply both sides of equation (1) by 10, the equation can be obtained: , then add the two sides of equation (8) to both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (2) by 8, the equation can be obtained: , then subtract both sides of equation (9) from both sides of equation (4), the equations are reduced to:
Multiply both sides of equation (2) by 20, the equation can be obtained: | -20 | B | + | | 20 | C | + | | 20 | D | = | | 0 | (10) | , then add the two sides of equation (10) to both sides of equation (5), the equations are reduced to:
交After the exchange of equation (3) and equation (4), the equation system becomes:
Multiply both sides of equation (3) by 3, the equation can be obtained: | -24 | C | | -48 | D | | -6 | F | = | | -120 | (11) | , then add the two sides of equation (11) to both sides of equation (5), the equations are reduced to:
Divide the two sides of equation (3) by 2, the equation can be obtained: , then subtract both sides of equation (12) from both sides of equation (6), the equations are reduced to:
Multiply both sides of equation (4) by 28, the equation can be obtained: , then subtract both sides of equation (13) from both sides of equation (5), the equations are reduced to:
Multiply both sides of equation (4) by 16, the equation can be obtained: , then add the two sides of equation (14) to both sides of equation (6), the equations are reduced to:
Multiply both sides of equation (5) by 6 Divide the two sides of equation (5) by 7, the equation can be obtained: , then add the two sides of equation (15) to both sides of equation (6), the equations are reduced to:
Multiply both sides of equation (6) by 308 Divide both sides of equation (6) by 145, get the equation:, then subtract both sides of equation (16) from both sides of equation (5), get the equation:
Multiply both sides of equation (6) by 7 Divide both sides of equation (6) by 145, get the equation:, then add the two sides of equation (17) to both sides of equation (4), get the equation:
Multiply both sides of equation (6) by 14 Divide both sides of equation (6) by 145, get the equation:, then subtract both sides of equation (18) from both sides of equation (3), get the equation:
Multiply both sides of equation (6) by 7 Divide both sides of equation (6) by 145, get the equation:, then subtract both sides of equation (19) from both sides of equation (1), get the equation:
Divide both sides of equation (5) by 28, get the equation:, then add the two sides of equation (20) to both sides of equation (4), get the equation:
Multiply both sides of equation (4) by 16, get the equation:, then subtract both sides of equation (21) from both sides of equation (3), get the equation:
Add both sides of equation (4) to both sides of equation (2), get the equation:
Divide both sides of equation (3) by 8, get the equation:, then add the two sides of equation (22) to both sides of equation (2), get the equation:
Add both sides of equation (2) to both sides of equation (1), get the equation:
The coefficient of the unknown number is reduced to 1, and the equations are reduced to:
Therefore, the solution of the equation set is:
Convert the solution of the equation set to decimals:
解方程组的详细方法请参阅:《多元一次方程组的解法》 |