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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （n（13-2n+15））/2 = 0 .
Question type: Equation
Solution:Original question:
| ( | n | ( | 13 | − | 2 | n | + | 15 | ) | ) | ÷ | 2 | = | 0 |
| Left side of the equation = | n | ( | 13 | − | 2 | n | + | 15 | ) | × | 1 2 |
| = | n | × | 13 | × | 1 2 | − | n | × | 2 | n | × | 1 2 | + | n | × | 15 | × | 1 2 |
| = | n | × | 13 2 | − | n | × | 1 | n | + | n | × | 15 2 |
| = | 14 | n | − | n | × | 1 | n |
| 14 | n | − | n | × | 1 | n | = | 0 |
After the equation is converted into a general formula, it is converted into:
( n +0 )( n - 14 )=0
From
n + 0 = 0
n - 14 = 0
it is concluded that:：
n1=0
n2=14
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》