Mathematics
         
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    Current location:Mathematical operation > History of Mathematical Computation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (x/2×2+3-9×1-4×9÷9+9-3+4)×2-(1×2×3+1)×20 = 0 .
    Question type: Equation
    Solution:Original question:
     ( x ÷ 2 × 2 + 39 × 14 × 9 ÷ 9 + 93 + 4) × 2(1 × 2 × 3 + 1) × 20 = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = x ÷ 2 × 2 × 2 + 3 × 29 × 1 × 24 × 9 ÷ 9
                                             = x × 2 + 6188 + 186 + 8(1 × 2 × 3 + 1) × 20
                                             = 2 x 0(1 × 2 × 3 + 1) × 20
                                             = 2 x 01 × 2 × 3 × 201 × 20
                                             = 2 x 012020
                                             = 2 x 140
    The equation is transformed into :
     2 x 140 = 0

    Transposition :
     2 x = 0 + 140

    Combine the items on the right of the equation:
     2 x = 140

    The coefficient of the unknown number is reduced to 1 :
      x = 140 ÷ 2
        = 140 ×
1
2
        = 70 × 1

    We obtained :
      x = 70
    This is the solution of the equation.



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