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    Current location：Mathematical operation > History of Mathematical Computation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation （x/2×2+3-9×1-4×9÷9+9-3+4）×2-（1×2×3+1）×20 = 0 .
    Question type: Equation
    Solution:Original question:
     ( x ÷ 2 × 2 + 3 − 9 × 1 − 4 × 9 ÷ 9 + 9 − 3 + 4) × 2 − (1 × 2 × 3 + 1) × 20 = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = x ÷ 2 × 2 × 2 + 3 × 2 − 9 × 1 × 2 − 4 × 9 ÷ 9
                                             = x × 2 + 6 − 18 − 8 + 18 − 6 + 8 − (1 × 2 × 3 + 1) × 20
                                             = 2 x − 0 − (1 × 2 × 3 + 1) × 20
                                             = 2 x − 0 − 1 × 2 × 3 × 20 − 1 × 20
                                             = 2 x − 0 − 120 − 20
                                             = 2 x − 140
    The equation is transformed into :
     2 x − 140 = 0

    Transposition :
     2 x = 0 + 140

    Combine the items on the right of the equation:
     2 x = 140

    The coefficient of the unknown number is reduced to 1 :
      x = 140 ÷ 2
        = 140 ×
1
2
        = 70 × 1

    We obtained :
      x = 70
    This is the solution of the equation.



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