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    Current location:Mathematical operation > History of Mathematical Computation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation 1+1/(1300×(10/70×10^3+20)/(500-35))×((5000/500))^2×1 .
    Question type: Mathematical calculation
    Solution:
          1+1/(1300×(10/70×10^3+20)/(500-35))×((5000/500))^2×1
        =1+1/(1300×162.857/(500-35))×((5000/500))^2×1
        =1+1/(1300×162.857/465)×((5000/500))^2×1
        =1+1/455.29914×((5000/500))^2×1
        =1+1/455.29914×(10)^2×1
        =1+1/455.29914×10^2×1
        =1+1/455.29914×100×1
        =1+0.002196×100×1
        =1+0.2196×1
        =1+0.2196
        =1.2196

    Answer:1+1/(1300×(10/70×10^3+20)/(500-35))×((5000/500))^2×1=1.2196


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