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Enter the mathematical formula directly and click the "Next" button to get the calculation answer.
It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 arithmetic calculations
[1/1 Formula]
Work: Calculate the value of equation 1+1/(1300×((90+80+61.39)/2558.1×10^3+20)/(600-35))×((8000/600))^2×1 .
Question type: Mathematical calculation
Solution:
1+1/(1300×((90+80+61.39)/2558.1×10^3+20)/(600-35))×((8000/600))^2×1
=1+1/(1300×(231.39/2558.1×10^3+20)/(600-35))×((8000/600))^2×1
=1+1/(1300×110.454/(600-35))×((8000/600))^2×1
=1+1/(1300×110.454/565)×((8000/600))^2×1
=1+1/254.141947×((8000/600))^2×1
=1+1/254.141947×(13.333333)^2×1
=1+1/254.141947×13.333333^2×1
=1+1/254.141947×177.777768888889×1
=1+0.003935×177.777768888889×1
=1+0.699556×1
=1+0.699556
=1.699556
Answer:1+1/(1300×((90+80+61.39)/2558.1×10^3+20)/(600-35))×((8000/600))^2×1=1.699556