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Enter the mathematical formula directly and click the "Next" button to get the calculation answer.
It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 arithmetic calculations
[1/1 Formula]
Work: Calculate the value of equation -2*√(2×9.81×0.003×0.3)×log(10,((0.0003/(3.7×0.3)+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3))))) .
Question type: Mathematical calculation
Solution:
-2*√(2×9.81×0.003×0.3)×log(10,((0.0003/(3.7×0.3)+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3)))))
=-2*√0.017658×log(10,((0.0003/(3.7×0.3)+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3)))))
=-2*√0.017658×log(10,((0.0003/1.11+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3)))))
=-2*√0.017658×log(10,((0.0003/1.11+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3)))))
=-2*√0.017658×log(10,((0.0003/1.11+0.000003/(0.225×√(2×9.81×0.003×0.3)))))
=-2*√0.017658×log(10,((0.0003/1.11+0.000003/(0.225×√0.017658))))
=-2*√0.017658×log(10,((0.0003/1.11+0.000003/0.029899)))
=-2*√0.017658×log(10,(0.00037))
=-2*√0.017658×log(10,0.00037)
=-2*√0.017658×(-3.431798)
=-2*0.132883×-3.431798
=-0.265766×(-3.431798)
=0.912055
Answer:-2*√(2×9.81×0.003×0.3)×log(10,((0.0003/(3.7×0.3)+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3)))))=0.912055
☆1 arithmetic calculations
[1/1 Formula]
Work: Calculate the value of equation -2*√(2×9.81×0.003×0.3)×log(10,((0.0003/(3.7×0.3)+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3))))) .
Question type: Mathematical calculation
Solution:
-2*√(2×9.81×0.003×0.3)×log(10,((0.0003/(3.7×0.3)+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3)))))
=-2*√0.017658×log(10,((0.0003/(3.7×0.3)+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3)))))
=-2*√0.017658×log(10,((0.0003/1.11+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3)))))
=-2*√0.017658×log(10,((0.0003/1.11+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3)))))
=-2*√0.017658×log(10,((0.0003/1.11+0.000003/(0.225×√(2×9.81×0.003×0.3)))))
=-2*√0.017658×log(10,((0.0003/1.11+0.000003/(0.225×√0.017658))))
=-2*√0.017658×log(10,((0.0003/1.11+0.000003/0.029899)))
=-2*√0.017658×log(10,(0.00037))
=-2*√0.017658×log(10,0.00037)
=-2*√0.017658×(-3.431798)
=-2*0.132883×-3.431798
=-0.265766×(-3.431798)
=0.912055
Answer:-2*√(2×9.81×0.003×0.3)×log(10,((0.0003/(3.7×0.3)+(2.5×1.14×10^(-6))/(0.225×√(2×9.81×0.003×0.3)))))=0.912055