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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （x-3）（x-1/5） = 0 .
Question type: Equation
Solution:Original question:
| ( | x | − | 3 | ) | ( | x | − | 1 | ÷ | 5 | ) | = | 0 |
| Left side of the equation = | x | ( | x | − | 1 | ÷ | 5 | ) | − | 3 | ( | x | − | 1 | ÷ | 5 | ) |
| = | x | x | − | x | × | 1 | ÷ | 5 | − | 3 | ( | x | − | 1 | ÷ | 5 | ) |
| = | x | x | − | x | × | 1 5 | − | 3 | ( | x | − | 1 | ÷ | 5 | ) |
| = | x | x | − | 1 5 | x | − | 3 | x | + | 3 | × | 1 | ÷ | 5 |
| = | x | x | − | 1 5 | x | − | 3 | x | + | 3 5 |
| = | x | x | − | 16 5 | x | + | 3 5 |
| x | x | − | 16 5 | x | + | 3 5 | = | 0 |
After the equation is converted into a general formula, it is converted into:
( 5x - 1 )( x - 3 )=0
From
5x - 1 = 0
x - 3 = 0
it is concluded that:：
| x1= | 1 5 |
| x2=3 |
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》