Mathematics
         
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    Current location:Mathematical operation > History of Mathematical Computation > Answer
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           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation (0.5×22+2.4×19.1+2.5×22+20-10×(0.5+2.4+2.5))×0.33-2×0×√0.33+10×(0.5+2.4+2.5) .
    Question type: Mathematical calculation
    Solution:
          (0.5×22+2.4×19.1+2.5×22+20-10×(0.5+2.4+2.5))×0.33-2×0×√0.33+10×(0.5+2.4+2.5)
        =(0.5×22+2.4×19.1+2.5×22+20-10×5.4)×0.33-2×0×√0.33+10×(0.5+2.4+2.5)
        =77.84×0.33-2×0×√0.33+10×(0.5+2.4+2.5)
        =77.84×0.33-2×0×√0.33+10×5.4
        =77.84×0.33-2×0×0.574456+10×5.4
        =25.6872-2×0×0.574456+10×5.4
        =25.6872-0×0.574456+10×5.4
        =25.6872-0+10×5.4
        =25.6872-0+54
        =25.6872+54
        =79.6872

    Answer:(0.5×22+2.4×19.1+2.5×22+20-10×(0.5+2.4+2.5))×0.33-2×0×√0.33+10×(0.5+2.4+2.5)=79.6872


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