Mathematics
         
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    Current location:Mathematical operation > History of Mathematical Computation > Answer

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           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation lg5^2+(2/3)*lg8+lg5*lg20+(lg2)^2 .
    Question type: Mathematical calculation
    Solution:
          lg5^2+(2/3)*lg8+lg5*lg20+(lg2)^2
        =lg5^2+0.666667*lg8+lg5*lg20+(lg2)^2
        =lg5^2+0.666667*lg8+lg5*lg20+0.30103^2
        =0.69897^2+0.666667*lg8+lg5*lg20+0.301030^2
        =0.69897^2+0.666667*0.90309+lg5*lg20+0.301030^2
        =0.69897^2+0.666667*0.90309+0.69897*lg20+0.301030^2
        =0.69897^2+0.666667*0.90309+0.69897*1.30103+0.301030^2
        =0.4885590609+0.666667*0.90309+0.69897*1.30103+0.30103^2
        =0.4885590609+0.666667*0.90309+0.69897*1.30103+0.0906190609
        =0.4885590609+0.60206+0.69897*1.30103+0.0906190609
        =0.4885590609+0.60206+0.909381+0.0906190609
        =1.090619+0.909381+0.0906190609
        =2+0.0906190609
        =2.090619

    Answer:lg5^2+(2/3)*lg8+lg5*lg20+(lg2)^2=2.090619


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