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Mathematical calculation:
    Enter the mathematical formula directly and click the "Next" button to get the calculation answer.
    It supports mathematical functions (including trigonometric functions).
    Current location:Mathematical operation > History of Mathematical Computation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 integer calculations

[1/1 Integer column vertical calculation]
    Question type: Integer division
    Original question: 1000000000000000000000000000000000000000000000000000000000000000000000000000000000001/603812429055411or{blue}{函数的第 1 阶导数:}\\&\frac{d\left( \frac{\frac{1}{2}ln(\frac{-x}{sqrt(2sqrt(3) - y^{2} + 1)} + 1)}{sqrt(2sqrt(3) - y^{2} + 1)} + ln(x) + \frac{x}{y^{3}}\right)}{dx}\\=&\frac{\frac{1}{2}(\frac{-1}{sqrt(2sqrt(3) - y^{2} + 1)} - \frac{x*-(2*0*\frac{1}{2}*3^{\frac{1}{2}} + 0 + 0)*\frac{1}{2}}{(2sqrt(3) - y^{2} + 1)(2sqrt(3) - y^{2} + 1)^{\frac{1}{2}}} + 0)}{(\frac{-x}{sqrt(2sqrt(3) - y^{2} + 1)} + 1)sqrt(2sqrt(3) - y^{2} + 1)} + \frac{\frac{1}{2}ln(\frac{-x}{sqrt(2sqrt(3) - y^{2} + 1)} + 1)*-(2*0*\frac{1}{2}*3^{\frac{1}{2}} + 0 + 0)*\frac{1}{2}}{(2sqrt(3) - y^{2} + 1)(2sqrt(3) - y^{2} + 1)^{\frac{1}{2}}} + \frac{1}{(x)} + \frac{1}{y^{3}}\\=&\frac{-1}{2(\frac{-x}{sqrt(2sqrt(3) - y^{2} + 1)} + 1)sqrt(2sqrt(3) - y^{2} + 1)^{2}} + \frac{1}{x} + \frac{1}{y^{3}}\\ \end{split}\end{equation} \]





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