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[1/1 Formula]
    Work: Calculate the value of equation (1^2+2^2)/(1*2)+(2^2+3^2)/(2*3)+(3^2+4^2)/(3*4)+0.|+(2017^2+2018^2)/(2017*2018) .
    Question type: Mathematical calculation
    Solution:
          (1^2+2^2)/(1*2)+(2^2+3^2)/(2*3)+(3^2+4^2)/(3*4)+0.|+(2017^2+2018^2)/(2017*2018)
        =5/(1*2)+(2^2+3^2)/(2*3)+(3^2+4^2)/(3*4)+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+(2^2+3^2)/(2*3)+(3^2+4^2)/(3*4)+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+13/(2*3)+(3^2+4^2)/(3*4)+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+13/6+(3^2+4^2)/(3*4)+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+13/6+25/(3*4)+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+13/6+25/12+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+13/6+25/12+0.+8140613/(2017*2018)
        =5/2+13/6+25/12+0.+8140613/4070306
        =2.5+13/6+25/12+0+8140613/4070306
        =2.5+2.166667+25/12+0+8140613/4070306
        =2.5+2.166667+2.083333+0+8140613/4070306
        =2.5+2.166667+2.083333+0+2
        =4.666667+2.083333+0+2
        =6.75+0+2
        =6.75+2
        =8.75

    Answer:(1^2+2^2)/(1*2)+(2^2+3^2)/(2*3)+(3^2+4^2)/(3*4)+0.|+(2017^2+2018^2)/(2017*2018)=8.75


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