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    Current location:Mathematical operation > History of Mathematical Computation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation 1/3*sin(15)+2*cos5-2.5-1/3*sin0-2*cos0 .
    Question type: Mathematical calculation
    Solution:
          1/3*sin(15)+2*cos5-2.5-1/3*sin0-2*cos0
        =1/3*sin15+2*cos5-2.5-1/3*sin0-2*cos0
        =1/3*0.650288+2*cos5-2.5-1/3*sin0-2*cos0
        =1/3*0.650288+2*0.283662-2.5-1/3*sin0-2*cos0
        =1/3*0.650288+2*0.283662-2.5-1/3*0-2*cos0
        =1/3*0.650288+2*0.283662-2.5-1/3*0-2*1
        =0.333333*0.650288+2*0.283662-2.5-1/3*0-2*1
        =0.216762+2*0.283662-2.5-1/3*0-2*1
        =0.216762+0.567324-2.5-1/3*0-2*1
        =0.216762+0.567324-2.5-0.333333*0-2*1
        =0.216762+0.567324-2.5-0-2*1
        =0.216762+0.567324-2.5-0-2
        =0.784086-2.5-0-2
        =-1.715914-0-2
        =-1.715914-2
        =-3.715914

    Answer:1/3*sin(15)+2*cos5-2.5-1/3*sin0-2*cos0=-3.715914
    Note: Radian


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