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Work: Calculate the value of equation 16*1/32*log(128,1/32)+112*1/224*log(128,1/224) .
Question type: Mathematical calculation
Solution:
16*1/32*log(128,1/32)+112*1/224*log(128,1/224)
=16*1/32*(-0.714286)+112*1/224*log(128,1/224)
=16*1/32*(-0.714286)+112*1/224*(-1.11535)
=16/32*(-0.714286)+112*1/224*(-1.11535)
=0.5*(-0.714286)+112*1/224*(-1.11535)
=(-0.357143)+112*1/224*(-1.11535)
=-0.357143+112/224*(-1.11535)
=-0.357143+0.5*(-1.11535)
=-0.357143+(-0.557675)
=-0.914818 Answer:16*1/32*log(128,1/32)+112*1/224*log(128,1/224)=-0.914818Your problem has not been solved here? Please go to the Hot Problems section!