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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 arithmetic calculations
[1/1 Formula]
Work: Calculate the value of equation -2500-2000/(1+0.2)+1200×((1+0.2)^9-1)÷0.2÷(1+0.2)^9÷(1+0.2) .
Question type: Mathematical calculation
Solution:
-2500-2000/(1+0.2)+1200×((1+0.2)^9-1)÷0.2÷(1+0.2)^9÷(1+0.2)
=-2500-2000/1.2+1200×((1+0.2)^9-1)÷0.2÷(1+0.2)^9÷(1+0.2)
=-2500-2000/1.2+1200×(1.2^9-1)÷0.2÷(1+0.2)^9÷(1+0.2)
=-2500-2000/1.2+1200×4.15978÷0.2÷(1+0.2)^9÷(1+0.2)
=-2500-2000/1.2+1200×4.15978÷0.2÷1.2^9÷(1+0.2)
=-2500-2000/1.2+1200×4.15978÷0.2÷1.2^9÷1.2
=-2500-2000/1.2+1200×4.15978÷0.2÷5.159780351999999÷1.2
=-2500-1666.666667+1200×4.15978÷0.2÷5.159780351999999÷1.2
=-2500-1666.666667+4991.736÷0.2÷5.159780351999999÷1.2
=-2500-1666.666667+24958.68÷5.159780351999999÷1.2
=-2500-1666.666667+4837.159394÷1.2
=-2500-1666.666667+4030.966162
=-4166.666667+4030.966162
=-135.700505
Answer:-2500-2000/(1+0.2)+1200×((1+0.2)^9-1)÷0.2÷(1+0.2)^9÷(1+0.2)=-135.700505