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           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation π/2+(π/2)*sin(π/2)-π*sin(π/4)-π/2+2*cos(π/2) .
    Question type: Mathematical calculation
    Solution:
          π/2+(π/2)*sin(π/2)-π*sin(π/4)-π/2+2*cos(π/2)
        =π/2+1.570796*sin(π/2)-π*sin(π/4)-π/2+2*cos(π/2)
        =π/2+1.570796*sin1.570796-π*sin(π/4)-π/2+2*cos(π/2)
        =π/2+1.570796*sin1.570796-π*sin0.785398-π/2+2*cos(π/2)
        =π/2+1.570796*sin1.570796-π*sin0.785398-π/2+2*cos1.570796
        =π/2+1.570796*1-π*sin0.785398-π/2+2*cos1.570796
        =π/2+1.570796*1-π*0.707107-π/2+2*cos1.570796
        =π/2+1.570796*1-π*0.707107-π/2+2*0
        =1.570796+1.570796*1-π*0.707107-π/2+2*0
        =1.570796+1.570796-π*0.707107-π/2+2*0
        =1.570796+1.570796-2.221442-π/2+2*0
        =1.570796+1.570796-2.221442-1.570796+2*0
        =1.570796+1.570796-2.221442-1.570796+0
        =3.141592-2.221442-1.570796+0
        =0.92015-1.570796+0
        =-0.650646+0
        =-0.650646

    Answer:π/2+(π/2)*sin(π/2)-π*sin(π/4)-π/2+2*cos(π/2)=-0.650646
    Note: Radian


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