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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation 7x(2x－1)－3(4x－1)－2x(x+3)+1 = 0 .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
The solution of the equation:
x1≈0.174639 , keep 6 decimal places
x2≈1.908694 , keep 6 decimal places
There are 2 solution(s).
解程的详细方法请参阅：《方程的解法》
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation 7x(2x－1)－3(4x－1)－2x(x+3)+1 = 0 .
Question type: Equation
Solution:Original question:
| 7 | x | ( | 2 | x | − | 1 | ) | − | 3 | ( | 4 | x | − | 1 | ) | − | 2 | x | ( | x | + | 3 | ) | + | 1 | = | 0 |
| Left side of the equation = | 7 | x | × | 2 | x | − | 7 | x | × | 1 | − | 3 | ( | 4 | x | − | 1 | ) | − | 2 | x | ( | x | + | 3 | ) |
| = | 14 | x | x | − | 7 | x | − | 3 | ( | 4 | x | − | 1 | ) | − | 2 | x | ( | x | + | 3 | ) | + | 1 |
| = | 14 | x | x | − | 7 | x | − | 3 | × | 4 | x | + | 3 | × | 1 | − | 2 | x |
| = | 14 | x | x | − | 7 | x | − | 12 | x | + | 3 | − | 2 | x | ( | x | + | 3 | ) | + | 1 |
| = | 14 | x | x | − | 19 | x | + | 4 | − | 2 | x | ( | x | + | 3 | ) |
| = | 14 | x | x | − | 19 | x | + | 4 | − | 2 | x | x | − | 2 | x | × | 3 |
| = | 14 | x | x | − | 19 | x | + | 4 | − | 2 | x | x | − | 6 | x |
| = | 14 | x | x | − | 25 | x | + | 4 | − | 2 | x | x |
| 14 | x | x | − | 25 | x | + | 4 | − | 2 | x | x | = | 0 |
The solution of the equation:
x1≈0.174639 , keep 6 decimal places
x2≈1.908694 , keep 6 decimal places
There are 2 solution(s).
解程的详细方法请参阅：《方程的解法》