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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation (d+2)*(d+5)+d*(d+5)+d*(d+2) = 0 .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
The solution of the equation:
d1≈-3.786300 , keep 6 decimal places
d2≈-0.880367 , keep 6 decimal places
There are 2 solution(s).
解程的详细方法请参阅：《方程的解法》
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation (d+2)*(d+5)+d*(d+5)+d*(d+2) = 0 .
Question type: Equation
Solution:Original question:
| ( | d | + | 2 | ) | ( | d | + | 5 | ) | + | d | ( | d | + | 5 | ) | + | d | ( | d | + | 2 | ) | = | 0 |
| Left side of the equation = | d | ( | d | + | 5 | ) | + | 2 | ( | d | + | 5 | ) | + | d | ( | d | + | 5 | ) | + | d | ( | d | + | 2 | ) |
| = | d | d | + | d | × | 5 | + | 2 | ( | d | + | 5 | ) | + | d | ( | d | + | 5 | ) | + | d | ( | d | + | 2 | ) |
| = | d | d | + | 5 | d | + | 2 | d | + | 2 | × | 5 | + | d | ( | d | + | 5 | ) | + | d | ( | d | + | 2 | ) |
| = | d | d | + | 5 | d | + | 2 | d | + | 10 | + | d | ( | d | + | 5 | ) | + | d | ( | d | + | 2 | ) |
| = | d | d | + | 7 | d | + | 10 | + | d | ( | d | + | 5 | ) | + | d | ( | d | + | 2 | ) |
| = | d | d | + | 7 | d | + | 10 | + | d | d | + | d | × | 5 | + | d | ( | d | + | 2 | ) |
| = | d | d | + | 12 | d | + | 10 | + | d | d | + | d | ( | d | + | 2 | ) |
| = | d | d | + | 12 | d | + | 10 | + | d | d | + | d | d | + | d | × | 2 |
| = | d | d | + | 14 | d | + | 10 | + | d | d | + | d | d |
| d | d | + | 14 | d | + | 10 | + | d | d | + | d | d | = | 0 |
The solution of the equation:
d1≈-3.786300 , keep 6 decimal places
d2≈-0.880367 , keep 6 decimal places
There are 2 solution(s).
解程的详细方法请参阅：《方程的解法》