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Work: Calculate the value of equation C(3,0)*2^0+C(3,1)*2^1+C(3,2)*2^2+C(3,3)*2^3 .
Question type: Mathematical calculation
Solution:
C(3,0)*2^0+C(3,1)*2^1+C(3,2)*2^2+C(3,3)*2^3
=1*2^0+C(3,1)*2^1+C(3,2)*2^2+C(3,3)*2^3
=1*2^0+3*2^1+C(3,2)*2^2+C(3,3)*2^3
=1*2^0+3*2^1+3*2^2+C(3,3)*2^3
=1*2^0+3*2^1+3*2^2+1*2^3
=1*1+3*2^1+3*2^2+1*2^3
=1*1+3*2+3*2^2+1*2^3
=1*1+3*2+3*4+1*2^3
=1*1+3*2+3*4+1*8
=1+3*2+3*4+1*8
=1+6+3*4+1*8
=1+6+12+1*8
=1+6+12+8
=7+12+8
=19+8
=27 Answer:C(3,0)*2^0+C(3,1)*2^1+C(3,2)*2^2+C(3,3)*2^3=27Your problem has not been solved here? Please go to the Hot Problems section!