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Mathematical calculation:
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    Current location:Mathematical operation > History of Mathematical Computation > Answer
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           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation C(3,0)*2^0+C(3,1)*2^1+C(3,2)*2^2+C(3,3)*2^3 .
    Question type: Mathematical calculation
    Solution:
          C(3,0)*2^0+C(3,1)*2^1+C(3,2)*2^2+C(3,3)*2^3
        =1*2^0+C(3,1)*2^1+C(3,2)*2^2+C(3,3)*2^3
        =1*2^0+3*2^1+C(3,2)*2^2+C(3,3)*2^3
        =1*2^0+3*2^1+3*2^2+C(3,3)*2^3
        =1*2^0+3*2^1+3*2^2+1*2^3
        =1*1+3*2^1+3*2^2+1*2^3
        =1*1+3*2+3*2^2+1*2^3
        =1*1+3*2+3*4+1*2^3
        =1*1+3*2+3*4+1*8
        =1+3*2+3*4+1*8
        =1+6+3*4+1*8
        =1+6+12+1*8
        =1+6+12+8
        =7+12+8
        =19+8
        =27

    Answer:C(3,0)*2^0+C(3,1)*2^1+C(3,2)*2^2+C(3,3)*2^3=27


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