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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （x-20）（-2x+80） = 0 .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
After the equation is converted into a general formula, it is converted into:
( x - 20 )( x - 40 )=0
From
x - 20 = 0
x - 40 = 0
it is concluded that:：
x1=20
x2=40
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation （x-20）（-2x+80） = 0 .
Question type: Equation
Solution:Original question:
| ( | x | − | 20 | ) | ( | - | 2 | x | + | 80 | ) | = | 0 |
| Left side of the equation = | x | ( | - | 2 | x | + | 80 | ) | − | 20 | ( | - | 2 | x | + | 80 | ) |
| = | - | x | × | 2 | x | + | x | × | 80 | − | 20 | ( | - | 2 | x | + | 80 | ) |
| = | - | x | × | 2 | x | + | 80 | x | + | 20 | × | 2 | x | − | 20 | × | 80 |
| = | - | x | × | 2 | x | + | 80 | x | + | 40 | x | − | 1600 |
| = | - | x | × | 2 | x | + | 120 | x | − | 1600 |
| - | x | × | 2 | x | + | 120 | x | − | 1600 | = | 0 |
After the equation is converted into a general formula, it is converted into:
( x - 20 )( x - 40 )=0
From
x - 20 = 0
x - 40 = 0
it is concluded that:：
x1=20
x2=40
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》