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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation x[1200-30（x-30）] = 36750 .
Question type: Equation
Solution:Original question:
Remove the bracket on the left of the equation:
The equation is transformed into :
After the equation is converted into a general formula, it is converted into:
( x - 35 )( x - 35 )=0
From
x - 35 = 0
x - 35 = 0
it is concluded that:：
x1=35
x2=35
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation x[1200-30（x-30）] = 36750 .
Question type: Equation
Solution:Original question:
| x | ( | 1200 | − | 30 | ( | x | − | 30 | ) | ) | = | 36750 |
| Left side of the equation = | x | × | 1200 | − | x | × | 30 | ( | x | − | 30 | ) |
| = | 1200 | x | − | x | × | 30 | x | + | x | × | 30 | × | 30 |
| = | 1200 | x | − | x | × | 30 | x | + | x | × | 900 |
| = | 2100 | x | − | x | × | 30 | x |
| 2100 | x | − | x | × | 30 | x | = | 36750 |
After the equation is converted into a general formula, it is converted into:
( x - 35 )( x - 35 )=0
From
x - 35 = 0
x - 35 = 0
it is concluded that:：
x1=35
x2=35
There are 2 solution(s).
解一元二次方程的详细方法请参阅：《一元二次方程的解法》