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[1/1 Formula]
Work: Calculate the value of equation (1-log(6,3))^2+log(6,2)*log(6,18) .
Question type: Mathematical calculation
Solution:
(1-log(6,3))^2+log(6,2)*log(6,18)
=(1-0.613147)^2+log(6,2)*log(6,18)
=0.386853^2+log(6,2)*log(6,18)
=0.386853^2+0.386853*log(6,18)
=0.386853^2+0.386853*1.613147
=0.149655243609+0.386853*1.613147
=0.149655243609+0.624051
=0.773706 Answer:(1-log(6,3))^2+log(6,2)*log(6,18)=0.773706Your problem has not been solved here? Please go to the Hot Problems section!