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Fractions calculation：
Enter the fractions calculation formula directly and click the "Next" button to get the calculation answer.
It does not support mathematical functions (including trigonometric functions) and can only calculate the addition, subtraction, multiplication and division of two fractions. The fraction line is indicated by "/".
Enter the fractions calculation formula directly and click the "Next" button to get the calculation answer.
It does not support mathematical functions (including trigonometric functions) and can only calculate the addition, subtraction, multiplication and division of two fractions. The fraction line is indicated by "/".
Current location：Mathematical operation > History of fraction calculation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation 0.5x+5 = 0.6x-75 .
Question type: Equation
Solution:Original question:
Transposition :
Combine the items on the left of the equation:
Combine the items on the right of the equation:
By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
☆1 equations
[ 1/1 Equation]
Work: Find the solution of equation 0.5x+5 = 0.6x-75 .
Question type: Equation
Solution:Original question:
1 2 | x | + | 5 | = | 3 5 | x | − | 75 |
Transposition :
1 2 | x | − | 3 5 | x | = | - | 75 | − | 5 |
Combine the items on the left of the equation:
| - | 1 10 | x | = | - | 75 | − | 5 |
Combine the items on the right of the equation:
| - | 1 10 | x | = | - | 80 |
By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
| 80 | = | 1 10 | x |
If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
1 10 | x | = | 80 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 80 | ÷ | 1 10 |
| = | 80 | × | 10 |
We obtained :
| x | = | 800 |