There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
Note that variables are case sensitive.\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ \frac{1}{2}k{x}^{2} + \frac{1}{2}k{(2x - y)}^{2} - 2pl({x}^{2} + \frac{1}{2}{y}^{2} - xy) - pl({x}^{2} + {y}^{2} - xy)\ with\ respect\ to\ x:\\\end{split}\end{equation} \]
\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = \frac{5}{2}kx^{2} - 2kyx + \frac{1}{2}ky^{2} - 3plx^{2} + 3yplx - 2y^{2}pl\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( \frac{5}{2}kx^{2} - 2kyx + \frac{1}{2}ky^{2} - 3plx^{2} + 3yplx - 2y^{2}pl\right)}{dx}\\=&\frac{5}{2}k*2x - 2ky + 0 - 3pl*2x + 3ypl + 0\\=&5kx - 2ky - 6plx + 3ypl\\ \end{split}\end{equation} \]Your problem has not been solved here? Please go to the Hot Problems section!