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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation x = 6.65*0.1495/(2.85+6.65)+2.85*0.06*0.65/(2.85+6.65) .
    Question type: Equation
    Solution:Original question:
      x =
133
20
 ×
299
2000
 ÷ (
57
20
 +
133
20
) +
57
20
 ×
3
50
 ×
13
20
 ÷ (
57
20
 +
133
20
)
     Multiply both sides of the equation by:(
57
20
 +
133
20
)
      x (
57
20
 +
133
20
) =
133
20
 ×
299
2000
 +
57
20
 ×
3
50
 ×
13
20
 ÷ (
57
20
 +
133
20
) × (
57
20
 +
133
20
)
    Remove a bracket on the left of the equation:：
      x ×
57
20
 + x ×
133
20
 =
133
20
 ×
299
2000
 +
57
20
 ×
3
50
 ×
13
20
 ÷ (
57
20
 +
133
20
) × (
57
20
 +
133
20
)
    Remove a bracket on the right of the equation:：
      x ×
57
20
 + x ×
133
20
 =
133
20
 ×
299
2000
 +
57
20
 ×
3
50
 ×
13
20
 ÷ (
57
20
 +
133
20
) ×
57
20
 +
57
20
 ×
3
50
 ×
13
20
 ÷ (
57
20
 +
133
20
) ×
133
20
    The equation is reduced to :
      x ×
57
20
 + x ×
133
20
 =
39767
40000
 +
126711
400000
 ÷ (
57
20
 +
133
20
) +
295659
400000
 ÷ (
57
20
 +
133
20
)
    The equation is reduced to :
     
19
2
 x =
39767
40000
 +
126711
400000
 ÷ (
57
20
 +
133
20
) +
295659
400000
 ÷ (
57
20
 +
133
20
)
     Multiply both sides of the equation by:(
57
20
 +
133
20
)
     
19
2
 x (
57
20
 +
133
20
) =
39767
40000
(
57
20
 +
133
20
) +
126711
400000
 +
295659
400000
 ÷ (
57
20
 +
133
20
) × (
57
20
 +
133
20
)
    Remove a bracket on the left of the equation:
     
19
2
 x ×
57
20
 +
19
2
 x ×
133
20
 =
39767
40000
(
57
20
 +
133
20
) +
126711
400000
 +
295659
400000
 ÷ (
57
20
 +
133
20
) × (
57
20
 +
133
20
)
    Remove a bracket on the right of the equation:：
     
19
2
 x ×
57
20
 +
19
2
 x ×
133
20
 =
39767
40000
 ×
57
20
 +
39767
40000
 ×
133
20
 +
126711
400000
 +
295659
400000
 ÷ (
57
20
 +
133
20
) × (
57
20
 +
133
20
)
    The equation is reduced to :
     
1083
40
 x +
2527
40
 x =
2266719
800000
 +
5289011
800000
 +
126711
400000
 +
295659
400000
 ÷ (
57
20
 +
133
20
) × (
57
20
 +
133
20
)

    
        x=
2327
20000
    
    There are 1 solution(s).

解一元一次方程的详细方法请参阅：《一元一次方程的解法》


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