301 25 | c | = | ( | 17 5 | + | c | ) | × | 159 20 |
| Right side of the equation = | 17 5 | × | 159 20 | + | c | × | 159 20 |
| = | 2703 100 | + | c | × | 159 20 |
301 25 | c | = | 2703 100 | + | 159 20 | c |
301 25 | c | − | 159 20 | c | = | 2703 100 |
409 100 | c | = | 2703 100 |
| c | = | 2703 100 | ÷ | 409 100 |
| = | 2703 100 | × | 100 409 |
| = | 2703 | × | 1 409 |
| c | = | 2703 409 |
| c | = | 6.608802 |