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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 36.96/(1+x/12*3)+0.04/(1+x/12*13) = 35.56 .
    Question type: Equation
    Solution:Original question:
     
924
25
 ÷ (1 + x ÷ 12 × 3) +
1
25
 ÷ (1 + x ÷ 12 × 13) =
889
25
     Multiply both sides of the equation by:(1 + x ÷ 12 × 3)
     
924
25
 +
1
25
 ÷ (1 + x ÷ 12 × 13) × (1 + x ÷ 12 × 3) =
889
25
(1 + x ÷ 12 × 3)
    Remove a bracket on the left of the equation:：
     
924
25
 +
1
25
 ÷ (1 + x ÷ 12 × 13) × 1 +
1
25
 ÷ (1 + x ÷ 12 × 13) × x ÷ 12 × 3 =
889
25
(1 + x ÷ 12 × 3)
    Remove a bracket on the right of the equation:：
     
924
25
 +
1
25
 ÷ (1 + x ÷ 12 × 13) × 1 +
1
25
 ÷ (1 + x ÷ 12 × 13) × x ÷ 12 × 3 =
889
25
 × 1 +
889
25
 x ÷ 12 × 3
    The equation is reduced to :
     
924
25
 +
1
25
 ÷ (1 + x ÷ 12 × 13) +
1
100
 ÷ (1 + x ÷ 12 × 13) × x =
889
25
 +
889
100
 x
     Multiply both sides of the equation by:(1 + x ÷ 12 × 13)
     
924
25
(1 + x ÷ 12 × 13) +
1
25
 +
1
100
 x =
889
25
(1 + x ÷ 12 × 13) +
889
100
 x (1 + x ÷ 12 × 13)
    Remove a bracket on the left of the equation:
     
924
25
 × 1 +
924
25
 x ÷ 12 × 13 +
1
25
 +
1
100
 x =
889
25
(1 + x ÷ 12 × 13) +
889
100
 x (1 + x ÷ 12 × 13)
    Remove a bracket on the right of the equation:：
     
924
25
 × 1 +
924
25
 x ÷ 12 × 13 +
1
25
 +
1
100
 x =
889
25
 × 1 +
889
25
 x ÷ 12 × 13 +
889
100
 x (1 + x ÷ 12 × 13)
    The equation is reduced to :
     
924
25
 +
1001
25
 x +
1
25
 +
1
100
 x =
889
25
 +
11557
300
 x +
889
100
 x (1 + x ÷ 12 × 13)
    The equation is reduced to :
     37 +
801
20
 x =
889
25
 +
11557
300
 x +
889
100
 x (1 + x ÷ 12 × 13)
    Remove a bracket on the right of the equation:：
     37 +
801
20
 x =
889
25
 +
11557
300
 x +
889
100
 x × 1 +
889
100
 x x ÷ 12 × 13
    The equation is reduced to :
     37 +
801
20
 x =
889
25
 +
11557
300
 x +
889
100
 x +
11557
1200
 x x
    The equation is reduced to :
     37 +
801
20
 x =
889
25
 +
3556
75
 x +
11557
1200
 x x

    
        x≈0.161464 , keep 6 decimal places    
    There are 1 solution(s).

解一元一次方程的详细方法请参阅：《一元一次方程的解法》


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