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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation X+30+(X+30)/（1−0.003）×0.003 = 400 .
    Question type: Equation
    Solution:Original question:
      X + 30 + ( X + 30) ÷ (1 −
3
1000
) ×
3
1000
 = 400
     Multiply both sides of the equation by:(1 −
3
1000
)
      X (1 −
3
1000
) + 30(1 −
3
1000
) + ( X + 30) ×
3
1000
 = 400(1 −
3
1000
)
    Remove a bracket on the left of the equation:：
      X × 1 − X ×
3
1000
 + 30(1 −
3
1000
) + ( X + 30) ×
3
1000
 = 400(1 −
3
1000
)
    Remove a bracket on the right of the equation:：
      X × 1 − X ×
3
1000
 + 30(1 −
3
1000
) + ( X + 30) ×
3
1000
 = 400 × 1 − 400 ×
3
1000
    The equation is reduced to :
      X × 1 − X ×
3
1000
 + 30(1 −
3
1000
) + ( X + 30) ×
3
1000
 = 400 −
6
5
    The equation is reduced to :
     
997
1000
 X + 30(1 −
3
1000
) + ( X + 30) ×
3
1000
 =
1994
5
    Remove a bracket on the left of the equation:
     
997
1000
 X + 30 × 1 − 30 ×
3
1000
 + ( X + 30) ×
3
1000
 =
1994
5
    The equation is reduced to :
     
997
1000
 X + 30 −
9
100
 + ( X + 30) ×
3
1000
 =
1994
5
    The equation is reduced to :
     
997
1000
 X +
2991
100
 + ( X + 30) ×
3
1000
 =
1994
5
    Remove a bracket on the left of the equation:
     
997
1000
 X +
2991
100
 + X ×
3
1000
 + 30 ×
3
1000
 =
1994
5
    The equation is reduced to :
     
997
1000
 X +
2991
100
 + X ×
3
1000
 +
9
100
 =
1994
5
    The equation is reduced to :
     1 X + 30 =
1994
5

    Transposition :
     1 X =
1994
5
 − 30
    i.e.
      X =
1994
5
 − 30

    Combine the items on the right of the equation:
      X =
1844
5
    This is the solution of the equation.
    This is the solution of the equation.



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