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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 0.353*(f+f-0.21)+0.399*(f-0.21+f-5.59)+7.310*(f-5.59+f-9.79) = 6*140*195*2/1000 .
    Question type: Equation
    Solution:Original question:
     
353
1000
( f + f
21
100
) +
399
1000
( f
21
100
+ f
559
100
) +
731
100
( f
559
100
+ f
979
100
) = 6 × 140 × 195 × 2 ÷ 1000
    Remove the bracket on the left of the equation:
     Left side of the equation =
353
1000
f +
353
1000
f
353
1000
×
21
100
+
399
1000
( f
21
100
+ f
559
100
) +
731
100
( f
559
100
+ f
979
100
)
                                             =
353
1000
f +
353
1000
f
7413
100000
+
399
1000
( f
21
100
+ f
559
100
) +
731
100
( f
559
100
+ f
979
100
)
                                             =
353
500
f
7413
100000
+
399
1000
( f
21
100
+ f
559
100
) +
731
100
( f
559
100
+ f
979
100
)
                                             =
353
500
f
7413
100000
+
399
1000
f
399
1000
×
21
100
+
399
1000
f
399
1000
×
559
100
+
731
100
                                             =
353
500
f
7413
100000
+
399
1000
f
8379
100000
+
399
1000
f
223041
100000
+
731
100
( f
559
100
+ f
979
100
)
                                             =
188
125
f
238833
100000
+
731
100
( f
559
100
+ f
979
100
)
                                             =
188
125
f
238833
100000
+
731
100
f
731
100
×
559
100
+
731
100
f
731
100
×
979
100
                                             =
188
125
f
238833
100000
+
731
100
f
408629
10000
+
731
100
f
715649
10000

    
        f≈27.438361 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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