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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 0.813*(f+f-0.48)+1.341*(f-0.48+f-14.10)+6.060*(f-14.10+f-17.51) = 6*140*195*2/1000 .
    Question type: Equation
    Solution:Original question:
     
813
1000
( f + f
12
25
) +
1341
1000
( f
12
25
+ f
141
10
) +
303
50
( f
141
10
+ f
1751
100
) = 6 × 140 × 195 × 2 ÷ 1000
    Remove the bracket on the left of the equation:
     Left side of the equation =
813
1000
f +
813
1000
f
813
1000
×
12
25
+
1341
1000
( f
12
25
+ f
141
10
) +
303
50
( f
141
10
+ f
1751
100
)
                                             =
813
1000
f +
813
1000
f
2439
6250
+
1341
1000
( f
12
25
+ f
141
10
) +
303
50
( f
141
10
+ f
1751
100
)
                                             =
813
500
f
2439
6250
+
1341
1000
( f
12
25
+ f
141
10
) +
303
50
( f
141
10
+ f
1751
100
)
                                             =
813
500
f
2439
6250
+
1341
1000
f
1341
1000
×
12
25
+
1341
1000
f
1341
1000
×
141
10
+
303
50
                                             =
813
500
f
2439
6250
+
1341
1000
f
4023
6250
+
1341
1000
f
189081
10000
+
303
50
( f
141
10
+ f
1751
100
)
                                             =
1077
250
f
997101
50000
+
303
50
( f
141
10
+ f
1751
100
)
                                             =
1077
250
f
997101
50000
+
303
50
f
303
50
×
141
10
+
303
50
f
303
50
×
1751
100
                                             =
1077
250
f
997101
50000
+
303
50
f
42723
500
+
303
50
f
530553
5000

    
        f≈32.815840 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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