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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (0.7*(11499m+3055.5*0.1+432/m+84.34)-(3740.9+322.32*0.1+796.13m))/408 = 1.05 .
    Question type: Equation
    Solution:Original question:
     (
7
10
(11499 m +
6111
2
×
1
10
+ 432 ÷ m +
4217
50
)(
37409
10
+
8058
25
×
1
10
+
79613
100
m )) ÷ 408 =
21
20
    Remove a bracket on the left of the equation::
     
7
10
(11499 m +
6111
2
×
1
10
+ 432 ÷ m +
4217
50
) ÷ 408(
37409
10
+
8058
25
×
1
10
+
79613
100
m ) ÷ 408 =
21
20
    The equation is reduced to :
     
7
4080
(11499 m +
6111
2
×
1
10
+ 432 ÷ m +
4217
50
)(
37409
10
+
8058
25
×
1
10
+
79613
100
m ) ×
1
408
=
21
20
    Remove a bracket on the left of the equation:
     
7
4080
× 11499 m +
7
4080
×
6111
2
×
1
10
+
7
4080
× 432 ÷ m +
7
4080
×
4217
50
(
37409
10
+
8058
25
×
1
10
+
79613
100
m ) =
21
20
    The equation is reduced to :
     
26831
1360
m +
14259
27200
+
63
85
÷ m +
29519
204000
(
37409
10
+
8058
25
×
1
10
+
79613
100
m ) ×
1
408
=
21
20
    The equation is reduced to :
     
26831
1360
m +
272923
408000
+
63
85
÷ m (
37409
10
+
8058
25
×
1
10
+
79613
100
m ) ×
1
408
=
21
20
     Multiply both sides of the equation by: m
     
26831
1360
m m +
272923
408000
m +
63
85
(
37409
10
+
8058
25
×
1
10
+
79613
100
m ) ×
1
408
m =
21
20
m
    Remove a bracket on the left of the equation:
     
26831
1360
m m +
272923
408000
m +
63
85
37409
10
×
1
408
m
8058
25
×
1
10
×
1
408
=
21
20
m
    The equation is reduced to :
     
26831
1360
m m +
272923
408000
m +
63
85
37409
4080
m
79
1000
m
79613
40800
m =
21
20
m

    The solution of the equation:
        m1≈0.092912 , keep 6 decimal places
        m2≈0.448729 , keep 6 decimal places
    
    There are 2 solution(s).


解程的详细方法请参阅:《方程的解法》



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