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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (0.0028x+0.25)/(1-0.0022x) = (0.75-0.0038)/(0.58+0.0028x) .
    Question type: Equation
    Solution:Original question:
     (
7
2500
x +
1
4
) ÷ (1
11
5000
x ) = (
3
4
19
5000
) ÷ (
29
50
+
7
2500
x )
     Multiply both sides of the equation by:(1
11
5000
x ) ,  (
29
50
+
7
2500
x )
     (
7
2500
x +
1
4
)(
29
50
+
7
2500
x ) = (
3
4
19
5000
)(1
11
5000
x )
    Remove a bracket on the left of the equation::
     
7
2500
x (
29
50
+
7
2500
x ) +
1
4
(
29
50
+
7
2500
x ) = (
3
4
19
5000
)(1
11
5000
x )
    Remove a bracket on the right of the equation::
     
7
2500
x (
29
50
+
7
2500
x ) +
1
4
(
29
50
+
7
2500
x ) =
3
4
(1
11
5000
x )
19
5000
(1
11
5000
x )
    Remove a bracket on the left of the equation:
     
7
2500
x ×
29
50
+
7
2500
x ×
7
2500
x +
1
4
(
29
50
+
7
2500
x ) =
3
4
(1
11
5000
x )
19
5000
(1
11
5000
x )
    Remove a bracket on the right of the equation::
     
7
2500
x ×
29
50
+
7
2500
x ×
7
2500
x +
1
4
(
29
50
+
7
2500
x ) =
3
4
× 1
3
4
×
11
5000
x
19
5000
(1
11
5000
x )
    The equation is reduced to :
     
203
125000
x +
49
6250000
x x +
1
4
(
29
50
+
7
2500
x ) =
3
4
33
20000
x
19
5000
(1
11
5000
x )
    Remove a bracket on the left of the equation:
     
203
125000
x +
49
6250000
x x +
1
4
×
29
50
+
1
4
×
7
2500
x =
3
4
33
20000
x
19
5000
(1
11
5000
x )
    Remove a bracket on the right of the equation::
     
203
125000
x +
49
6250000
x x +
1
4
×
29
50
+
1
4
×
7
2500
x =
3
4
33
20000
x
19
5000
× 1 +
19
5000
×
11
5000
x
    The equation is reduced to :
     
203
125000
x +
49
6250000
x x +
29
200
+
7
10000
x =
3
4
33
20000
x
19
5000
+
209
25000000
x

    
        x≈122.119288 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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