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On line Solution of Monovariate Equation：
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
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    Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 0.1 = （0.08*（（1/（0.7-0.15））*（1-X））/（1-0.08*（（1/（0.7-0.15））*（1-X））） ) .
    Question type: Equation
    Solution:Original question:
     
1
10
 = (
2
25
((1 ÷ (
7
10
 −
3
20
))(1 − X )) ÷ (1 −
2
25
((1 ÷ (
7
10
 −
3
20
))(1 − X ))))
    Remove a bracket on the right of the equation:：
     
1
10
 =
2
25
((1 ÷ (
7
10
 −
3
20
))(1 − X )) ÷ (1 −
2
25
((1 ÷ (
7
10
 −
3
20
))(1 − X )))
     Multiply both sides of the equation by:(1 −
2
25
((1 ÷ (
7
10
 −
3
20
))(1 − X )))
     
1
10
(1 −
2
25
((1 ÷ (
7
10
 −
3
20
))(1 − X ))) =
2
25
((1 ÷ (
7
10
 −
3
20
))(1 − X ))
    Remove a bracket on the left of the equation:
     
1
10
 × 1 −
1
10
 ×
2
25
((1 ÷ (
7
10
 −
3
20
))(1 − X )) =
2
25
((1 ÷ (
7
10
 −
3
20
))(1 − X ))
    Remove a bracket on the right of the equation:：
     
1
10
 × 1 −
1
10
 ×
2
25
((1 ÷ (
7
10
 −
3
20
))(1 − X )) =
2
25
(1 ÷ (
7
10
 −
3
20
))(1 − X )
    The equation is reduced to :
     
1
10
 −
1
125
((1 ÷ (
7
10
 −
3
20
))(1 − X )) =
2
25
(1 ÷ (
7
10
 −
3
20
))(1 − X )
    Remove a bracket on the left of the equation:
     
1
10
 −
1
125
(1 ÷ (
7
10
 −
3
20
))(1 − X ) =
2
25
(1 ÷ (
7
10
 −
3
20
))(1 − X )
    Remove a bracket on the right of the equation:：
     
1
10
 −
1
125
(1 ÷ (
7
10
 −
3
20
))(1 − X ) =
2
25
 × 1 ÷ (
7
10
 −
3
20
) × (1 − X )
    The equation is reduced to :
     
1
10
 −
1
125
(1 ÷ (
7
10
 −
3
20
))(1 − X ) =
2
25
 ÷ (
7
10
 −
3
20
) × (1 − X )
     Multiply both sides of the equation by:(
7
10
 −
3
20
)
     
1
10
(
7
10
 −
3
20
) −
1
125
(1 ÷ (
7
10
 −
3
20
))(1 − X )(
7
10
 −
3
20
) =
2
25
(1 − X )
    Remove a bracket on the left of the equation:
     
1
10
 ×
7
10
 −
1
10
 ×
3
20
 −
1
125
(1 ÷ (
7
10
 −
3
20
))(1 − X )(
7
10
 −
3
20
) =
2
25
(1 − X )
    Remove a bracket on the right of the equation:：
     
1
10
 ×
7
10
 −
1
10
 ×
3
20
 −
1
125
(1 ÷ (
7
10
 −
3
20
))(1 − X )(
7
10
 −
3
20
) =
2
25
 × 1 −
2
25
 X
    The equation is reduced to :
     
7
100
 −
3
200
 −
1
125
(1 ÷ (
7
10
 −
3
20
))(1 − X )(
7
10
 −
3
20
) =
2
25
 −
2
25
 X
    The equation is reduced to :
     
11
200
 −
1
125
(1 ÷ (
7
10
 −
3
20
))(1 − X )(
7
10
 −
3
20
) =
2
25
 −
2
25
 X
    Remove a bracket on the left of the equation:
     
11
200
 −
1
125
 × 1 ÷ (
7
10
 −
3
20
) × (1 − X )(
7
10
 −
3
20
) =
2
25
 −
2
25
 X
    The equation is reduced to :
     
11
200
 −
1
125
 ÷ (
7
10
 −
3
20
) × (1 − X )(
7
10
 −
3
20
) =
2
25
 −
2
25
 X
     Multiply both sides of the equation by:(
7
10
 −
3
20
)
     
11
200
(
7
10
 −
3
20
) −
1
125
(1 − X )(
7
10
 −
3
20
) =
2
25
(
7
10
 −
3
20
) −
2
25
 X (
7
10
 −
3
20
)
    Remove a bracket on the left of the equation:
     
11
200
 ×
7
10
 −
11
200
 ×
3
20
 −
1
125
(1 − X )(
7
10
 −
3
20
) =
2
25
(
7
10
 −
3
20
) −
2
25
 X (
7
10
 −
3
20
)
    Remove a bracket on the right of the equation:：
     
11
200
 ×
7
10
 −
11
200
 ×
3
20
 −
1
125
(1 − X )(
7
10
 −
3
20
) =
2
25
 ×
7
10
 −
2
25
 ×
3
20
 −
2
25
 X (
7
10
 −
3
20
)
    The equation is reduced to :
     
77
2000
 −
33
4000
 −
1
125
(1 − X )(
7
10
 −
3
20
) =
7
125
 −
3
250
 −
2
25
 X (
7
10
 −
3
20
)
    The equation is reduced to :
     
121
4000
 −
1
125
(1 − X )(
7
10
 −
3
20
) =
11
250
 −
2
25
 X (
7
10
 −
3
20
)
    Remove a bracket on the left of the equation:
     
121
4000
 −
1
125
 × 1(
7
10
 −
3
20
) +
1
125
 X (
7
10
 −
3
20
) =
11
250
 −
2
25
 X (
7
10
 −
3
20
)
    Remove a bracket on the right of the equation:：
     
121
4000
 −
1
125
 × 1(
7
10
 −
3
20
) +
1
125
 X (
7
10
 −
3
20
) =
11
250
 −
2
25
 X ×
7
10
 +
2
25
 X ×
3
20

    
        X1=
3
8
    
    There are 1 solution(s).

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