Mathematics
         
语言:中文    Language:English
                                Equations   
Fold
                                Unary equation
                                Multivariate equation
                                Math OP  
Unfold
                                Linear algebra      
Unfold
                                Derivative function
                                Function image
                                Hot issues
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation A-1000-(A-1000)/1.06×0.06-(A-1000)/1.06×0.06×12%-(A+1000)×0.03%-(A-1000-(A-1000)/1.06×0.06-(A-1000)/1.06×0.06×12%-(A+1000)×0.03%)×25% = 1000×3% .
    Question type: Equation
    Solution:Original question:
      A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) = 1000 ×
3
100
     Left side of the equation = A − 1000 − ( A − 1000) ×
3
53
− ( A − 1000) ×
9
1325
− ( A + 1000) ×
3
10000
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
    The equation is transformed into :
      A − 1000 − ( A − 1000) ×
3
53
− ( A − 1000) ×
9
1325
− ( A + 1000) ×
3
10000
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
= 1000 ×
3
100
    Remove the bracket on the left of the equation:
     Left side of the equation = A − 1000 − A ×
3
53
+ 1000 ×
3
53
− ( A − 1000) ×
9
1325
− ( A + 1000) ×
3
10000
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
                                             = A − 1000 − A ×
3
53
+
3000
53
− ( A − 1000) ×
9
1325
− ( A + 1000) ×
3
10000
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
                                             =
50
53
A −
50000
53
− ( A − 1000) ×
9
1325
− ( A + 1000) ×
3
10000
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
                                             =
50
53
A −
50000
53
− A ×
9
1325
+ 1000 ×
9
1325
− ( A + 1000) ×
3
10000
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
                                             =
50
53
A −
50000
53
− A ×
9
1325
+
360
53
− ( A + 1000) ×
3
10000
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
                                             =
1241
1325
A −
49640
53
− ( A + 1000) ×
3
10000
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
                                             =
1241
1325
A −
49640
53
− A ×
3
10000
− 1000 ×
3
10000
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
                                             =
1241
1325
A −
49640
53
− A ×
3
10000
−
3
10
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
                                             =
496241
530000
A −
496559
530
− ( A − 1000 − ( A − 1000) ÷
53
50
×
3
50
− ( A − 1000) ÷
53
50
×
3
50
×
12
100
− ( A + 1000) ×
3
10000
) ×
25
100
                                             =
496241
530000
A −
496559
530
− A ×
25
100
+ 1000 ×
25
100
+ ( A − 1000) ÷
53
50
×
3
50
×
25
100
+ ( A − 1000)
                                             =
496241
530000
A −
496559
530
− A ×
25
100
+ 250 + ( A − 1000) ×
3
212
+ ( A − 1000) ×
9
5300
+ ( A + 1000) ×
3
40000
                                             =
363741
530000
A −
364059
530
+ ( A − 1000) ×
3
212
+ ( A − 1000) ×
9
5300
+ ( A + 1000) ×
3
40000
                                             =
363741
530000
A −
364059
530
+ A ×
3
212
− 1000 ×
3
212
+ ( A − 1000) ×
9
5300
+ ( A + 1000) ×
3
40000
                                             =
363741
530000
A −
364059
530
+ A ×
3
212
−
750
53
+ ( A − 1000) ×
9
5300
+ ( A + 1000) ×
3
40000
                                             =
371241
530000
A −
371559
530
+ ( A − 1000) ×
9
5300
+ ( A + 1000) ×
3
40000
                                             =
371241
530000
A −
371559
530
+ A ×
9
5300
− 1000 ×
9
5300
+ ( A + 1000) ×
3
40000
                                             =
371241
530000
A −
371559
530
+ A ×
9
5300
−
90
53
+ ( A + 1000) ×
3
40000
                                             =
372141
530000
A −
372459
530
+ ( A + 1000) ×
3
40000
                                             =
372141
530000
A −
372459
530
+ A ×
3
40000
+ 1000 ×
3
40000
                                             =
372141
530000
A −
372459
530
+ A ×
3
40000
+
3
40

    
        A≈1043.361995 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



Your problem has not been solved here? Please go to the Hot Problems section!