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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 4.5945 = ((28.02*0.639(x+0.1))/(1+0.639(x+0.1))*((1-6.66-1.14)/100)*(1/(1+0.31*1.14)+((0.76(x+0.1))/(1.3*0.101325)) ) ) .
    Question type: Equation
    Solution:Original question:
     
9189
2000
= ((
1401
50
×
639
1000
( x +
1
10
)) ÷ (1 +
639
1000
( x +
1
10
)) × ((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
))))
    Remove a bracket on the right of the equation::
     
9189
2000
= (
1401
50
×
639
1000
( x +
1
10
)) ÷ (1 +
639
1000
( x +
1
10
)) × ((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
)))
     Multiply both sides of the equation by:(1 +
639
1000
( x +
1
10
))
     
9189
2000
(1 +
639
1000
( x +
1
10
)) = (
1401
50
×
639
1000
( x +
1
10
))((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
)))
    Remove a bracket on the left of the equation:
     
9189
2000
× 1 +
9189
2000
×
639
1000
( x +
1
10
) = (
1401
50
×
639
1000
( x +
1
10
))((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
)))
    Remove a bracket on the right of the equation::
     
9189
2000
× 1 +
9189
2000
×
639
1000
( x +
1
10
) =
1401
50
×
639
1000
( x +
1
10
)((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
)))
    The equation is reduced to :
     
9189
2000
+
5871771
2000000
( x +
1
10
) =
895239
50000
( x +
1
10
)((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
)))
    Remove a bracket on the left of the equation:
     
9189
2000
+
5871771
2000000
x +
5871771
2000000
×
1
10
=
895239
50000
( x +
1
10
)((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
)))
    Remove a bracket on the right of the equation::
     
9189
2000
+
5871771
2000000
x +
5871771
2000000
×
1
10
=
895239
50000
x ((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
))) +
895239
50000
×
1
10
((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
)))
    The equation is reduced to :
     
9189
2000
+
5871771
2000000
x +
5871771
20000000
=
895239
50000
x ((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
))) +
895239
500000
((1
333
50
57
50
) ÷ 100)(1 ÷ (1 +
31
100
×
57
50
) + ((
19
25
( x +
1
10
)) ÷ (
13
10
×
4053
40000
)))

    The solution of the equation:
        x1≈-1.664945 , keep 6 decimal places
        x2≈-1.297891 , keep 6 decimal places
    
    There are 2 solution(s).


解程的详细方法请参阅:《方程的解法》



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