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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/4*(-2%)+3/4*(10%)(1-a) = 0 .
    Question type: Equation
    Solution:Original question:
     1 ÷ 4 × ( -
2
100
) + 3 ÷ 4 × (
10
100
)(1 a ) = 0
     Left side of the equation =
1
4
( -
2
100
) +
3
4
(
10
100
)(1 a )
    The equation is transformed into :
     
1
4
( -
2
100
) +
3
4
(
10
100
)(1 a ) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = -
1
4
×
2
100
+
3
4
(
10
100
)(1 a )
                                             = -
1
200
+
3
4
(
10
100
)(1 a )
                                             = -
1
200
+
3
4
×
10
100
(1 a )
                                             = -
1
200
+
3
40
(1 a )
                                             = -
1
200
+
3
40
× 1
3
40
a
                                             = -
1
200
+
3
40
3
40
a
                                             =
7
100
3
40
a
    The equation is transformed into :
     
7
100
3
40
a = 0

    Transposition :
      -
3
40
a = 0
7
100

    Combine the items on the right of the equation:
      -
3
40
a = -
7
100

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     
7
100
=
3
40
a

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
3
40
a =
7
100

    The coefficient of the unknown number is reduced to 1 :
      a =
7
100
÷
3
40
        =
7
100
×
40
3
        =
7
5
×
2
3

    We obtained :
      a =
14
15
    This is the solution of the equation.

    Convert the result to decimal form :
      a = 0.933333



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