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    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (4n*n+2n)*(2n-1)*(2n-2) = 140(n*n-n)*(n-2) .
    Question type: Equation
    Solution:Original question:
     (4 n n + 2 n )(2 n 1)(2 n 2) = 140( n n n )( n 2)
    Remove the bracket on the left of the equation:
     Left side of the equation = 4 n n (2 n 1)(2 n 2) + 2 n (2 n 1)(2 n 2)
                                             = 4 n n × 2 n (2 n 2)4 n n × 1(2 n 2) + 2
                                             = 8 n n n (2 n 2)4 n n (2 n 2) + 2 n (2 n 1)
                                             = 8 n n n × 2 n 8 n n n × 24
                                             = 16 n n n n 16 n n n 4 n n
                                             = 16 n n n n 16 n n n 4 n n
                                             = 16 n n n n 16 n n n 8 n n
                                             = 16 n n n n 16 n n n 8 n n
                                             = 16 n n n n 16 n n n 8 n n
                                             = 16 n n n n 16 n n n 8 n n
                                             = 16 n n n n 16 n n n 8 n n
                                             = 16 n n n n 16 n n n 8 n n
                                             = 16 n n n n 16 n n n 8 n n
    The equation is transformed into :
     16 n n n n 16 n n n 8 n n = 140( n n n )( n 2)
    Remove the bracket on the right of the equation:
     Right side of the equation = 140 n n ( n 2)140 n ( n 2)
                                               = 140 n n n 140 n n × 2140 n ( n 2)
                                               = 140 n n n 280 n n 140 n ( n 2)
                                               = 140 n n n 280 n n 140 n n + 140 n
                                               = 140 n n n 280 n n 140 n n + 280 n
    The equation is transformed into :
     16 n n n n 16 n n n 8 n n = 140 n n n 280 n n 140 n n + 280 n

    After the equation is converted into a general formula, it is converted into:
    ( n - 0 )( n - 1 )( n - 3 )( 4n - 23 )=0
    From
        n - 0 = 0
        n - 1 = 0
        n - 3 = 0
        4n - 23 = 0

    it is concluded that::
        n1=0
        n2=1
        n3=3
        n4=
23
4
    
    There are 4 solution(s).


解程的详细方法请参阅:《方程的解法》



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