Overview: 5 questions will be solved this time.Among them
           ☆5 equations

[ 1/5 Equation]
    Work: Find the solution of equation 2x^2-13x+5 = 0 .
    Question type: Equation
    Solution:
    The solution of the equation:
        x₁≈0.410546 , keep 6 decimal places
        x₂≈6.089454 , keep 6 decimal places    
    There are 2 solution(s).

解程的详细方法请参阅：《方程的解法》
[ 2/5 Equation]
    Work: Find the solution of equation 6x^2-3x-3 = 0 .
    Question type: Equation
    Solution:
    After the equation is converted into a general formula, it is converted into:
    ( 2x + 1 )( x - 1 )=0
    From
        2x + 1 = 0
        x - 1 = 0
    it is concluded that:：

x1=

-

1 2

x2=1

    
    There are 2 solution(s).

解一元二次方程的详细方法请参阅：《一元二次方程的解法》
[ 3/5 Equation]
    Work: Find the solution of equation 6x^2-7x+2 = 0 .
    Question type: Equation
    Solution:
    After the equation is converted into a general formula, it is converted into:
    ( 2x - 1 )( 3x - 2 )=0
    From
        2x - 1 = 0
        3x - 2 = 0
    it is concluded that:：

x1=

1 2

x2=

2 3

    
    There are 2 solution(s).

解一元二次方程的详细方法请参阅：《一元二次方程的解法》
[ 4/5 Equation]
    Work: Find the solution of equation 3y^2-8y-4 = 0 .
    Question type: Equation
    Solution:
    The solution of the equation:
        y₁≈-0.430501 , keep 6 decimal places
        y₂≈3.097168 , keep 6 decimal places    
    There are 2 solution(s).

解程的详细方法请参阅：《方程的解法》
[ 5/5 Equation]
    Work: Find the solution of equation 6x^2+19x+10 = 0 .
    Question type: Equation
    Solution:
    After the equation is converted into a general formula, it is converted into:
    ( 2x + 5 )( 3x + 2 )=0
    From
        2x + 5 = 0
        3x + 2 = 0
    it is concluded that:：

x1=

-

5 2

x2=

-

2 3

    
    There are 2 solution(s).

解一元二次方程的详细方法请参阅：《一元二次方程的解法》

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