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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (x-x/3-100-(x-x/3-100)/4-100-(x-x/3-100-(x-x/3-100)/4-100)/5-100)/6+100 = 350 .
    Question type: Equation
    Solution:Original question:
     ( x x ÷ 3100( x x ÷ 3100) ÷ 4100( x x ÷ 3100( x x ÷ 3100) ÷ 4100) ÷ 5100) ÷ 6 + 100 = 350
    Remove the bracket on the left of the equation:
     Left side of the equation = x ×
1
6
x ÷ 3 ×
1
6
100 ×
1
6
( x x ÷ 3100) ÷ 4 ×
1
6
100 ×
1
6
                                             = x ×
1
6
x ×
1
18
50
3
( x x ÷ 3100) ×
1
24
50
3
( x x ÷ 3100( x x ÷ 3100) ÷ 4100) ×
1
30
50
3
+ 100
                                             =
1
9
x + 50( x x ÷ 3100) ×
1
24
( x x ÷ 3100( x x ÷ 3100) ÷ 4100) ×
1
30
                                             =
1
9
x + 50 x ×
1
24
+ x ÷ 3 ×
1
24
+ 100 ×
1
24
( x x ÷ 3100( x x ÷ 3100) ÷ 4100) ×
1
30
                                             =
1
9
x + 50 x ×
1
24
+ x ×
1
72
+
25
6
( x x ÷ 3100( x x ÷ 3100) ÷ 4100) ×
1
30
                                             =
1
12
x +
325
6
( x x ÷ 3100( x x ÷ 3100) ÷ 4100) ×
1
30
                                             =
1
12
x +
325
6
x ×
1
30
+ x ÷ 3 ×
1
30
+ 100 ×
1
30
+ ( x x ÷ 3100) ÷ 4
                                             =
1
12
x +
325
6
x ×
1
30
+ x ×
1
90
+
10
3
+ ( x x ÷ 3100) ×
1
120
+
10
3
                                             =
11
180
x +
365
6
+ ( x x ÷ 3100) ×
1
120
                                             =
11
180
x +
365
6
+ x ×
1
120
x ÷ 3 ×
1
120
100 ×
1
120
                                             =
11
180
x +
365
6
+ x ×
1
120
x ×
1
360
5
6
                                             =
1
15
x + 60
    The equation is transformed into :
     
1
15
x + 60 = 350

    Transposition :
     
1
15
x = 35060

    Combine the items on the right of the equation:
     
1
15
x = 290

    The coefficient of the unknown number is reduced to 1 :
      x = 290 ÷
1
15
        = 290 × 15

    We obtained :
      x = 4350
    This is the solution of the equation.



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