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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (5-xx)*2.5-0.5(x+3)(4.5-0.5xx)-0.5(2-x)(2-0.5xx) = 5 .
    Question type: Equation
    Solution:Original question:
     (5 x x ) ×
5
2
1
2
( x + 3)(
9
2
1
2
x x )
1
2
(2 x )(2
1
2
x x ) = 5
    Remove the bracket on the left of the equation:
     Left side of the equation = 5 ×
5
2
x x ×
5
2
1
2
( x + 3)(
9
2
1
2
x x )
1
2
(2 x )(2
1
2
x x )
                                             =
25
2
x x ×
5
2
1
2
( x + 3)(
9
2
1
2
x x )
1
2
(2 x )(2
1
2
x x )
                                             =
25
2
x x ×
5
2
1
2
x (
9
2
1
2
x x )
1
2
× 3(
9
2
1
2
x x )
1
2
(2 x )
                                             =
25
2
x x ×
5
2
1
2
x (
9
2
1
2
x x )
3
2
(
9
2
1
2
x x )
1
2
(2 x )(2
1
2
x x )
                                             =
25
2
x x ×
5
2
1
2
x ×
9
2
+
1
2
x ×
1
2
x x
                                             =
25
2
x x ×
5
2
9
4
x +
1
4
x x x
3
2
(
9
2
1
2
x x )
                                             =
25
2
x x ×
5
2
9
4
x +
1
4
x x x
3
2
×
9
2
                                             =
25
2
x x ×
5
2
9
4
x +
1
4
x x x
27
4
+
3
4
                                             =
23
4
x x ×
5
2
9
4
x +
1
4
x x x +
3
4
x
                                             =
23
4
x x ×
5
2
9
4
x +
1
4
x x x +
3
4
x
                                             =
23
4
x x ×
5
2
9
4
x +
1
4
x x x +
3
4
x
                                             =
23
4
x x ×
5
2
9
4
x +
1
4
x x x +
3
4
x
                                             =
23
4
x x ×
5
2
9
4
x +
1
4
x x x +
3
4
x
                                             =
15
4
x x ×
5
2
9
4
x +
1
4
x x x +
3
4
x
                                             =
15
4
x x ×
5
2
9
4
x +
1
4
x x x +
3
4
x
                                             =
15
4
x x ×
5
2
9
4
x +
1
4
x x x +
3
4
x
                                             =
15
4
x x ×
5
2
5
4
x +
1
4
x x x +
3
4
x
    The equation is transformed into :
     
15
4
x x ×
5
2
5
4
x +
1
4
x x x +
3
4
x = 5
    This equation has no real solution!


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