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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation x/150+30(x/150)*50%+(x/150)*10% = x+(x*40%) .
    Question type: Equation
    Solution:Original question:
      x ÷ 150 + 30( x ÷ 150) ×
50
100
+ ( x ÷ 150) ×
10
100
= x + ( x ×
40
100
)
     Left side of the equation = x ×
1
150
+ 15( x ÷ 150) + ( x ÷ 150) ×
10
100
    The equation is transformed into :
     
1
150
x + 15( x ÷ 150) + ( x ÷ 150) ×
10
100
= x + ( x ×
40
100
)
    Remove the bracket on the left of the equation:
     Left side of the equation =
1
150
x + 15 x ÷ 150 + ( x ÷ 150) ×
10
100
                                             =
1
150
x +
1
10
x + ( x ÷ 150) ×
10
100
                                             =
8
75
x + ( x ÷ 150) ×
10
100
                                             =
8
75
x + x ÷ 150 ×
10
100
                                             =
8
75
x + x ×
1
1500
                                             =
161
1500
x
    The equation is transformed into :
     
161
1500
x = x + ( x ×
40
100
)
    Remove the bracket on the right of the equation:
     Right side of the equation = x + x ×
40
100
                                               =
7
5
x
    The equation is transformed into :
     
161
1500
x =
7
5
x

    Transposition :
     
161
1500
x
7
5
x = 0

    Combine the items on the left of the equation:
      -
1939
1500
x = 0

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
      - 0 =
1939
1500
x

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
1939
1500
x = - 0

    The coefficient of the unknown number is reduced to 1 :
      x = - 0 ÷
1939
1500
        = - 0 ×
1500
1939

    We obtained :
      x = 0
    This is the solution of the equation.



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