Mathematics
         
语言:中文    Language:English
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/d+1/(d+1)+1/(d+10) = 1/d .
    Question type: Equation
    Solution:Original question:
     1 ÷ d + 1 ÷ ( d + 1) + 1 ÷ ( d + 10) = 1 ÷ d
     Multiply both sides of the equation by: d
     1 + 1 ÷ ( d + 1) × d + 1 ÷ ( d + 10) × d = 1 ÷ 1 × 1
     Multiply both sides of the equation by:( d + 1)
     1( d + 1) + 1 d + 1 ÷ ( d + 10) × d ( d + 1) = 1 ÷ 1 × 1( d + 1)
    Remove a bracket on the left of the equation:
     1 d + 1 × 1 + 1 d + 1 ÷ ( d + 10) × d ( d + 1) = 1 ÷ 1 × 1( d + 1)
    Remove a bracket on the right of the equation::
     1 d + 1 × 1 + 1 d + 1 ÷ ( d + 10) × d ( d + 1) = 1 ÷ 1 × 1 d + 1 ÷ 1 × 1 × 1
    The equation is reduced to :
     1 d + 1 + 1 d + 1 ÷ ( d + 10) × d ( d + 1) = 1 d + 1
    The equation is reduced to :
     2 d + 1 + 1 ÷ ( d + 10) × d ( d + 1) = 1 d + 1
     Multiply both sides of the equation by:( d + 10)
     2 d ( d + 10) + 1( d + 10) + 1 d ( d + 1) = 1 d ( d + 10) + 1( d + 10)
    Remove a bracket on the left of the equation:
     2 d d + 2 d × 10 + 1( d + 10) + 1 d ( d + 1) = 1 d ( d + 10) + 1( d + 10)
    Remove a bracket on the right of the equation::
     2 d d + 2 d × 10 + 1( d + 10) + 1 d ( d + 1) = 1 d d + 1 d × 10 + 1( d + 10)
    The equation is reduced to :
     2 d d + 20 d + 1( d + 10) + 1 d ( d + 1) = 1 d d + 10 d + 1( d + 10)
    Remove a bracket on the left of the equation:
     2 d d + 20 d + 1 d + 1 × 10 + 1 d ( d + 1) = 1 d d + 10 d + 1( d + 10)
    Remove a bracket on the right of the equation::
     2 d d + 20 d + 1 d + 1 × 10 + 1 d ( d + 1) = 1 d d + 10 d + 1 d + 1 × 10
    The equation is reduced to :
     2 d d + 20 d + 1 d + 10 + 1 d ( d + 1) = 1 d d + 10 d + 1 d + 10
    The equation is reduced to :
     2 d d + 21 d + 10 + 1 d ( d + 1) = 1 d d + 11 d + 10
    Remove a bracket on the left of the equation:
     2 d d + 21 d + 10 + 1 d d + 1 d × 1 = 1 d d + 11 d + 10
    The equation is reduced to :
     2 d d + 21 d + 10 + 1 d d + 1 d = 1 d d + 11 d + 10
    The equation is reduced to :
     2 d d + 22 d + 10 + 1 d d = 1 d d + 11 d + 10

    
        d1=-
11
2
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。