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    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1.5÷(5-x)+0.6÷(3-x)+0.3÷(1-x)+0.1÷(0.5-x) = 0 .
    Question type: Equation
    Solution:Original question:
     
3
2
÷ (5 x ) +
3
5
÷ (3 x ) +
3
10
÷ (1 x ) +
1
10
÷ (
1
2
x ) = 0
     Multiply both sides of the equation by:(5 x )
     
3
2
+
3
5
÷ (3 x ) × (5 x ) +
3
10
÷ (1 x ) × (5 x ) +
1
10
÷ (
1
2
x ) × (5 x ) = 0
    Remove a bracket on the left of the equation::
     
3
2
+
3
5
÷ (3 x ) × 5
3
5
÷ (3 x ) × x +
3
10
÷ (1 x ) × (5 x ) +
1
10
÷ (
1
2
x ) = 0
    The equation is reduced to :
     
3
2
+ 3 ÷ (3 x )
3
5
÷ (3 x ) × x +
3
10
÷ (1 x ) × (5 x ) +
1
10
÷ (
1
2
x ) × (5 x ) = 0
     Multiply both sides of the equation by:(3 x )
     
3
2
(3 x ) + 3
3
5
x +
3
10
÷ (1 x ) × (5 x )(3 x ) +
1
10
÷ (
1
2
x ) × (5 x ) = 0
    Remove a bracket on the left of the equation:
     
3
2
× 3
3
2
x + 3
3
5
x +
3
10
÷ (1 x ) × (5 x )(3 x ) +
1
10
= 0
    The equation is reduced to :
     
9
2
3
2
x + 3
3
5
x +
3
10
÷ (1 x ) × (5 x )(3 x ) +
1
10
÷ (
1
2
x ) = 0
    The equation is reduced to :
     
15
2
21
10
x +
3
10
÷ (1 x ) × (5 x )(3 x ) +
1
10
÷ (
1
2
x ) × (5 x )(3 x ) = 0
     Multiply both sides of the equation by:(1 x )
     
15
2
(1 x )
21
10
x (1 x ) +
3
10
(5 x )(3 x ) +
1
10
÷ (
1
2
x ) × (5 x )(3 x ) = 0
    Remove a bracket on the left of the equation:
     
15
2
× 1
15
2
x
21
10
x (1 x ) +
3
10
(5 x )(3 x ) +
1
10
÷ (
1
2
x ) = 0
    The equation is reduced to :
     
15
2
15
2
x
21
10
x (1 x ) +
3
10
(5 x )(3 x ) +
1
10
÷ (
1
2
x ) × (5 x ) = 0
     Multiply both sides of the equation by:(
1
2
x )
     
15
2
(
1
2
x )
15
2
x (
1
2
x )
21
10
x (1 x )(
1
2
x ) +
3
10
(5 x )(3 x ) = 0
    Remove a bracket on the left of the equation:
     
15
2
×
1
2
15
2
x
15
2
x (
1
2
x )
21
10
x (1 x )(
1
2
x ) +
3
10
= 0
    The equation is reduced to :
     
15
4
15
2
x
15
2
x (
1
2
x )
21
10
x (1 x )(
1
2
x ) +
3
10
(5 x ) = 0
    Remove a bracket on the left of the equation:
     
15
4
15
2
x
15
2
x ×
1
2
+
15
2
x x
21
10
x (1 x ) = 0
    The equation is reduced to :
     
15
4
15
2
x
15
4
x +
15
2
x x
21
10
x (1 x )(
1
2
x ) = 0
    The equation is reduced to :
     
15
4
45
4
x +
15
2
x x
21
10
x (1 x )(
1
2
x ) +
3
10
(5 x ) = 0
    Remove a bracket on the left of the equation:
     
15
4
45
4
x +
15
2
x x
21
10
x × 1(
1
2
x ) +
21
10
x = 0
    The equation is reduced to :
     
15
4
45
4
x +
15
2
x x
21
10
x (
1
2
x ) +
21
10
x x = 0
    Remove a bracket on the left of the equation:
     
15
4
45
4
x +
15
2
x x
21
10
x ×
1
2
+
21
10
x x = 0
    The equation is reduced to :
     
15
4
45
4
x +
15
2
x x
21
20
x +
21
10
x x +
21
10
= 0
    The equation is reduced to :
     
15
4
123
10
x +
15
2
x x +
21
10
x x +
21
10
x x = 0

    The solution of the equation:
        x1≈0.577145 , keep 6 decimal places
        x2≈1.431369 , keep 6 decimal places
        x3≈3.631485 , keep 6 decimal places
    
    There are 3 solution(s).


解程的详细方法请参阅:《方程的解法》



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